A wild-type fruit fly (heterozygous for gray body color and norma...

Question

A wild-type fruit fly (heterozygous for gray body color and normal wings) is mated with a black fly with vestigial wings. The offspring have the following phenotypic distribution: wild-type, 778; black vestigial, 785; black normal, 158; gray vestigial, 162. What is the recombination frequency between these genes for body color and wing size? Is this consistent with the results of the experiment in Figure 15.9?

Accepted Answer

Hello everyone here we have a question that says a wild type Drosophila which is hetero ziggy's for a great body and normal wings is made with a Drosophila with black body and vestigial wings. The fanatic pick distribution of the normal of the uh offspring is as follows. Wild type 1556 black with vestigial wings, 1570 gray with vestigial wings. 324. Black with normal wings 316. And the question is what will be the recombination frequency between the genes for body color and wing size? So first we need a formula for recombination frequency. So recombination frequency equals recombination offsprings over total offsprings. So now we need to calculate our recombinant offsprings are recombinant offsprings are not the same as either parent their their own. So our recombinant offspring will be Joseph villa with gray body and vestigial wings. So Plus Drosophila with black body and normal wings. So plus 316 And that equals 640. Now we need to calculate the total offsprings which was 1, Plus 1570 Plus 324 Plus 316. And that equals 3766. So our recommended frequency is going to equal Over 3, times 100 And that equals 17%. So our answer here is be 17%. Thank you for watching. Bye

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