All right guys, let's attempt to the example that was left on the bottom of the page. So here it says, determine the major product for the following halogen nation reaction. So again, we have two pie bonds. That's why we use two moles of BR two. So this carbon and this carbon is triple bonded carbons. Each one gets two halogens apiece because why we have two moles of BR two, which means we have a total of for BROM means at our disposal. So two of them will go to one triple bonded carbon. The other two will go to the other triple bonded carbon. And remember when we're adding bees, these will remove the pi bonds. So we have this ch three carbon here connected to this carbon which was once triple bonded, but no longer. It has now two BRS on it. It's connected to the other carbon that was triple bonded at one point but no longer. And it has two BRS on it. And then we're connected to the rest of the chain. So that's what we'd get there. We'd get four halogens being added and this would be called a tetra, meaning four Halid. So this would be a tetra halid. So just remember one mole of BR two or CL two helps to add two halogens onto a double bond. It removes the double bond to add two halogens. But here we have two pi bonds because it's a triple bond. So we need two moles of BR two to get our final answer.
