alright, guys in these next examples were given the name of the compound and asked to dry here. This may seem like a harder process, but actually drawing the compound from the name is actually easier. What you should do is start with the end of the name. The end of the name forms the chain, the base and we're gonna say here we have decade, which is 10 carbons. So ch three siege to siege to. So the hard part is writing all this out. Ch two ch two ch two c h eight, nine and then 10. Now on carbons 34 and five. There are metals, So 10. Now what you should notice you're at the moment is every single carbon is making four bonds. So when I put on those metal groups on carbons 34 and five, those carbons would be making five bonds too many bonds. So how do they compensate for this extra metal group? They lose Ah, hydrogen. So in carbon three with a race and H so that we can accommodate that incoming method group. Same thing for carbon four and same thing with carbon five. Okay, so that would be our structure. And there's a bomb between them. Okay, so we lose an HF of each of them so that we can accommodate that incoming method group. So this is something you need to remember. Carbon is Tetra Valent can't go beyond four bonds. That was key to getting the correct answer here. Now that we've done that, go to the next one again. Start with the end of the name that forms the chain itself and then place the substitution on the right carbon and you're done.