A 1.0-L buffer solution is 0.125 M in HNO2 and 0.145 M in
NaNO2....

Question

A 1.0-L buffer solution is 0.125 M in HNO2 and 0.145 M in 
NaNO2. Determine the concentrations of HNO2 and NaNO2 
after the addition of each substance: 
a. 1.5 g HCl

Accepted Answer

Everyone so as to consider 150 male leader buffer solution. That is 0.125 moller of hydrogen fluoride, 2.175 muller of sodium fluoride or as a copy of the concentration Of hydrogen fluoride and sodium fluoride. After the addition of 2.56 g hydrochloric acid. He's the first catholic. The molds of each have 2.56 grams of hydrochloric acid. And in one mold the molar mass. This is 1.008g. That's 35 .453g. Get 30 cents 461 g. We get 0.0702 walls of hash clerk acid. We know that modularity. The malls and they saw you. What about leaders? Another solution. We need to convert our volume into Leaders. F 250 male leaders And then one l of 1000 male leaders. Just give us 0.2 side leaders, 0.125 malls of hydrogen fluoride. In one liter 0.25 L of solution. We get 0.03 12 sides balls. How is your floor ride? We have 0.175 malls of sodium fluoride and one leader 0.25 L of solution. Get 0.04 375 balls upsetting for right. The hydrochloric acid is gonna consume studying fluoride since hydrochloric acid, sodium fluoride. There would be no sodium fluoride left and I will be converted to hydrogen fluoride. Gonna have malls of hydrogen fluoride. Final pictures on walls hydrogen fluoride, initial some malls of sodium fluoride. Initial Southern walls. How's your floor ride? Final Equals 0.03125 malls, 0.04 375 malls, 0.075 malls. So now we need to calculate the concentration. How's your floor ride and signing for a ride? So for sodium fluoride, it's going to be zero mauler and the hydrogen fluoride Gonna get 0.075 moles. What about 0.25 leaders. We get 0.3 smaller. Thanks for watching my video. And I hope it was helpful.

A 1.0-L buffer solution is 0.125 M in HNO2 and 0.145 M in NaNO2. Determine the concentrations of HNO2 and NaNO2 after the addition of each substance: a. 1.5 g HCl

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