(a) If Qc Kc, how must the reaction proceed to reach
equilibriu...

Question

(a) If Qc > Kc, how must the reaction proceed to reach
equilibrium?

Accepted Answer

Hello everyone today, we have been given the following problem true or false. When our case QC or reaction quotient is greater than our equilibrium constant, the reaction will not shift in any direction because the reaction is already in equilibrium. So depending on if Q is greater or less than K, our reaction will shift to attain that equilibrium by reaching that K C value. And so it says here that our QC is greater than our Casey. And so when this is the case, the reaction, it's actually going to shift and the reaction shifts in the reverse direction in order to maintain that equilibrium. So it does this to reach equilibrium. So this statement overall is false due to that reasoning. And with that, we have answered the question overall, I hope this helped. And until next time.

(a) If Qc > Kc, how must the reaction proceed to reach equilibrium?

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