With the exception of helium, the noble gases condense to
form s...

Question

With the exception of helium, the noble gases condense to form solids when they are cooled sufficiently. At temperatures below 83 K, argon forms a close-packed solid whose structure is shown below. (b) Is this value larger or smaller than the bonding atomic radius estimated for argon in Figure 7.7?

Accepted Answer

Hello everyone today. We have the following problem Temperatures below 115 Kelvin Krypton forms a close packed solid structure. Stone below is the radius of krypton and solid structure larger is the radius of krypton larger than its estimated bonding atomic radius. So for the radius in the solid structure we're going to take the relevant distance where two atoms of Krypton are touching. Which is this 3.98 am strong's here. And so we're going to say that the radius Is equal to that 3.98. Armstrong's divided by 2 to give us 1.99 extremes. And so the estimated bonding atomic radius based on the given is 112. When we get this from the periodic table provided here And so we can say that 112 PK m is equal to 1.12 hamstrings. And so based on that data is the radius of krypton and structure greater than its estimated bond and radius. And the answer is yes, the radius is greater. And so with that we have our final answer. I hope this helped. And until next time

With the exception of helium, the noble gases condense to form solids when they are cooled sufficiently. At temperatures below 83 K, argon forms a close-packed solid whose structure is shown below. (b) Is this value larger or smaller than the bonding atomic radius estimated for argon in Figure 7.7?

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