The value of Ka for nitrous acid 1HNO22 at 25 °C is given in Appe...

Question

The value of Ka for nitrous acid 1HNO22 at 25 °C is given in Appendix D. (b) By using the value of Ka, calculate ΔG° for the dissociation of nitrous acid in aqueous solution.

Accepted Answer

Hi everyone here we have a question asking us at 298 kelvin, what is the equilibrium constant K. And our reaction is zinc, sulfide solid plus oxygen. Gasses form zinc solid plus sulfate gashes. And our free energy of the reaction equals negative 101.8 kg per mole. So our free energy of the reaction equals R. Gas constant R negative gas constant times our temperature times the natural log of K. So okay equals E. To the negative free energy divided by our gas constant times our temperature. So E to the negative -101 .8 Killed Jules, Divided by 8.314 jules per mole times kelvin Times 298 Kelvin, And that equals 6.99, 1 Times 10 to the 17th. And that is our final answer. Thank you for watching. Bye.

The value of Ka for nitrous acid 1HNO22 at 25 °C is given in Appendix D. (b) By using the value of Ka, calculate ΔG° for the dissociation of nitrous acid in aqueous solution.

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