What is the melting point of benzene in kelvin if ΔHfusion = 9.95...

Question

What is the melting point of benzene in kelvin if ΔHfusion = 9.95 kJ>mol and ΔSfusion = 35.7 J> 1K mol2?

Accepted Answer

Hello everyone today we have a falling problem for nitro fennel is used as a ph indicator, calculate the melting point of four nitro phenol. So we're first gonna start with is our Gibbs free energy equation that says that the gibbs free energy is equal to the change in entropy minus our temperature times the change in our entropy. Moreover, we want to also note that at the melting point there are two important things. First they k values equal to one and our gifts for energy, A fusion is also equal, is going to be equal to zero. So in solving and plugging in our values, we're gonna put zero in for our gifts for energy. Our entropy change as stated here is 30.12 kg joules per mole. We're gonna subtract that. We do not have our temperature and they're multiplying by the entropy change Which is 78.20 jewels per Kelvin Mole, Solving for our temperature, we're going to get temperature is equal to our 30.12 kg per mole Divided by R0 Point 07820 killer jewels per kelvin mall. How do we get killed jules? Well we took our jewels here our 78. and we multiplied by the conversion factor that one kg jewels equal to 10 to the third jewels. And that's how we got 100.78 to 0 kg jewels Solving this out. We get a temperature of 385.17 Kelvin. However we want to get our melting point in degrees Celsius. So we're gonna do is we're going to sit here and we're going to subtract 2 73.15 from this value that we found. So our temperature is going to be 385.17 Kelvin -273.15 Kelvin, giving us a temperature of 112°C as our final answer. And with that we have answered the question overall. I hope this helped and until next time.

What is the melting point of benzene in kelvin if ΔHfusion = 9.95 kJ>mol and ΔSfusion = 35.7 J> 1K mol2?

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