Nalorphine 1C19H21NO3 2, a relative of morphine, is used to comba...

Question

Nalorphine 1C19H21NO3 2, a relative of morphine, is used to combat withdrawal symptoms in narcotics users. How many grams of a 1.3 * 10-3 m aqueous solution of nalor-phine are needed to obtain a dose of 1.5 mg?

Accepted Answer

Hey everyone, we're told that lidocaine is an anesthetic used to treat jellyfish stings, calculate the mass of 4.3 times 10 to the negative two mol a quick solution of lidocaine required to get a dosage of 100.0 mg. Now we've learned that our morality is equal to the mole of our solute, divided by the kilogram of our solvent. So first we're going to determine the kilogram of our solvent and then use that to determine the mass of our solution. Starting with 100 mg we're going to use dimensional analysis here. Now we know that per one mg, we have 10 to the negative 3rd g. And using lidocaine Mueller mass, We know that we have one mole of lidocaine and this will contain 234. g. Next we're going to divide this all by our 4.3 times 10 to the - moles per kilogram. Since this is our morality. Now, when we calculate this out and cancel out all of our units, we end up with a value of 9.9238 times 10 to the negative third kilograms of water. Now, given that the solution is dilute, we can assume that the density of solution is going to be equal to the density of our solvent. So to determine the mass of our solution, we can go ahead and take that value of 9.9 to 38 times to the negative third kilograms. And we can go ahead and convert this into grams. So we know that one kg contains 10 to the third grams. Now, when we calculate this out, we end up with a value of 9.9 g, which is going to be our final answer. Now, I hope that made sense and let us know if you have any questions.

Nalorphine 1C19H21NO3 2, a relative of morphine, is used to combat withdrawal symptoms in narcotics users. How many grams of a 1.3 * 10-3 m aqueous solution of nalor-phine are needed to obtain a dose of 1.5 mg?

Watch next