Consider this set of ionization energies.
IE1 = 578 kJmol
IE2 ...

Question

Consider this set of ionization energies. 
IE1 = 578 kJ>mol 
IE2 = 1820 kJ>mol 
IE3 = 2750 kJ>mol 
IE4 = 11,600 kJ>mol 
To which third-period element do these ionization values belong?

Accepted Answer

Hey everyone in this example, we need to identify which of these four elements below have the corresponding ionization energies listed here. So we want to go ahead and follow the pattern of the ionization energy. So at the first ionization energy we have An energy of 786 kg per mole. We increase at the second ionization energy to 1577 kg joules per mole. Then at the third ionization energy we increase even further to 35,000 sorry 3231 kg joules per mole. At the 4th ionization energy we go up to 4355 killed joules per mole. And then all of a sudden at the 5th ionization energy we go Up to a whopping 16,091 kg joules per mole. Now that is a major jump here and we want to go ahead and put an asterisk there because this is something we want to make a note of. So because we have a a big jump from previous ionization energy, which was the fourth ionization energy, we would say that therefore a core electron must have been removed. And so, to determine what our element is that matches these ionization energies, we would say That because we had a jump at i.e. or at the ionization energy, the fifth level of our ionization energy, we would say that therefore our element can only be found by focusing on our fourth ionization energy level. And so we have an element that has four valence electrons. And so we should recall that our valence electrons correspond to our group number, so that would correspond to group for A on our periodic table. And we should recall that the atom in Group four A on our periodic table with four valence electrons out of our answer choices is going to be be silicon. And so the only correct choice to complete this example is Choice B, which is the element that possesses the above ionization energies. So I hope that everything be explained was clear. If you have any questions, please leave them down below and I will see everyone in the next practice video.

Consider this set of ionization energies. IE1 = 578 kJ>mol IE2 = 1820 kJ>mol IE3 = 2750 kJ>mol IE4 = 11,600 kJ>mol To which third-period element do these ionization values belong?

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