Carbon dioxide, which is recognized as the major contributor
to g...

Question

Carbon dioxide, which is recognized as the major contributor
to global warming as a 'greenhouse gas,' is formed
when fossil fuels are combusted, as in electrical power
plants fueled by coal, oil, or natural gas. One potential way
to reduce the amount of CO2 added to the atmosphere is
to store it as a compressed gas in underground formations.
Consider a 1000-megawatt coal-fired power plant that produces
about 6 * 106 tons of CO2 per year. (a) Assuming
ideal-gas behavior, 101.3 kPa, and 27 C, calculate the volume
of CO2 produced by this power plant.

Accepted Answer

Hi everyone for this problem, we're told cement is the source of about 8% of the world's carbon dioxide emissions. The manufacturer of cement produces about .9 kg of carbon dioxide for every two kg of cement In 2021, 92 million metric tons of cement were produced in the United States. We need to calculate the volume of carbon dioxide emitted by cement production in the US in 2021. Assume that it behaves as an ideal gas under the conditions of 1 80 M and 25 degrees Celsius. So, our mission here is to calculate the volume of carbon dioxide emitted by cement production. Okay. And we're going to assume that it behaves as an ideal gas. So we need to recall the ideal gas law here and that is PV equals N R T. And we're looking to calculate volume. So we need to isolate this ideal gas law to solve for volume and we do that by dividing both sides by peak. So our equation that we're solving for here is volume is equal to N R T over P. So let's go ahead and get started. We want to know the volume of carbon dioxide emitted by cement production in the us and 2021. So how much cement Production did we have in 2021? That's going to be our starting point. So we had Million metric tons. OK, so let's go ahead and write that down. So we have 92 Million metric tons as an exponent is going to be 92 times 10 to the six tons. This is metric tons. Okay, so metric tons of cement. So we want to go from metric tons of cement to moles of carbon dioxide because n is moles. So in order to solve for moles, we need to convert from metric tons of cement, two moles of carbon dioxide. So let's go ahead and start off by converting this metric tons of cement to grams. Okay, Because once we do that, we can use the molar mass of carbon dioxide along with a multiple conversion. So that's going to be our first thing. So one metric ton is equal to kilograms. Okay, remember we're going from we're trying to go from metric tons to grams. Okay, So in the problem tells us, we have 0.9 kg of carbon dioxide for every kilogram of cement. So this is a conversion here 0.9 kg of carbon dioxide for every kilogram of cement. So we'll put that here. So for every one kg of cement, we have 0. kilograms of carbon dioxide. Okay, So let's just look at how our units cancel here, are metric tons, cancel our kilograms, cancel. So now we're in kilograms of carbon dioxide and we want moles of carbon dioxide. So we can convert this kilograms, two g by using our conversion in one kg there's 1000 grams. Okay, So our kilograms cancel. And now we're in grams of carbon dioxide but we want moles of carbon dioxide. So to go from grams of carbon dioxide, two moles of carbon dioxide. We need the molar mass of carbon dioxide and one mall of carbon dioxide there is The Molar mass is 44.01 g of carbon dioxide. Okay, So our grams cancel. And now we have the unit of moles of carbon dioxide, which is what we're looking for. So let's go ahead and solve So we know what our N is for our rearranged ideal gas law. We get 1.88 times to the 12th moles of carbon dioxide. Okay, So we have our moles. Our next thing is our our is our gas constant and this is a value. We should know this is 0.8 to Leaders times a T. M. Over more times kelvin t is temperature. And the problem, we're told we're going to assume that the ideal gas behaves at 1 80 M and 25 degrees Celsius. Our temperature is 25 degrees Celsius. But because our constant has temperature in kelvin, we need to convert this to kelvin and we do that by adding 273.15. So we have a temperature of 298. kelvin and then p they tell us is 1 80 M. Because we're assuming it behaves as an ideal gas under those conditions that they told us. So we have everything. We have N. We have our T and P. So all we need to do now is plug all of that in to solve for our volume of carbon dioxide emitted. So we have N Is 1. times 10 to the 12. No times are 0.08, Leaders times atmosphere over more times, kelvin times temperature. Our temperature is 298. Calvin. This is all over. P. RP is 1 80 M. Okay, so let's take a look at how our units cancel here because we're solving for volume, our unit that should be left over is leaders. Okay, so our moles cancel, Calvin, cancel a T. M cancel And look at their we're left with leader, which is perfect because we're solving for volume. So we get a volume a final volume of 4.60 times To the 13 leader. And this is going to be our final answer. This is the volume of carbon dioxide emitted by cement production in the us in 2021. That's the end of this problem. I hope this was helpful

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