An AM radio station broadcasts at 1000 kHz and its FM
partner bro...

Question

An AM radio station broadcasts at 1000 kHz and its FM
partner broadcasts at 100 MHz. Calculate and compare the
energy of the photons emitted by these two radio stations.

Accepted Answer

hey everyone in this example, we need to calculate the difference in energy of photons between a 1. times 10 to the 15th. Power hurts UV light and a 3.5 times 10 to the 12th. Power hurts infrared light. We're going to calculate that or we're going to recall that our formula for the energy of a photon is equal to Planck's constant, multiplied by our frequency. So first finding our energy of photons in UV light, We're going to take plank's constant, which we would recall is 6.626 times 10 to the negative 34th power jewels. Time seconds and multiplied by its frequency given in the prompt As 1.5 times 10 to the 15th. Power hurts. However we want to recall that hurts are also equivalent to inverse seconds. So we can interpret this as inverse seconds for our frequency. And so this allows us to cancel out our units of seconds, leaving us with jewels as our final unit for energy, which is what we want. And we're going to get a value equal to 9.9 times 10 to the negative 19th power jewels. So now calculating our energy of photons in infrared light, we would find again the plank's constant is the same here. So it's 6.626 times 10 to the negative 34th power jewels. Time seconds. And now we're going to multiply just like we did above to our Frequency given in the prompt as 3.5 times 10 to the 12th. Power hurts which were interpreting as inverse seconds since they're equivalent units. And so now we're also able to cancel out seconds here leaving us with jewels and what we're going to get is a energy or the energy of our infrared light equal to a value of 2.3 times 10 to the negative 21st power jewels. And just to make this clear, we're going to put this in the color purple for our energy of infrared light. So now we're going to take the difference between these two energies. So for UV light we said we have an energy of 9.9 times 10 to the negative 19th power jewels. And we're going to subtract that from our energy of infrared light which was 2.3 times 10 to the 21st to the negative 21st power jules. This difference gives us a final value equal to Final value of 9.9 times 10 to the negative 19th power jewels. And this would be the final answer for the difference in energy of the photons of UV light and infrared light. So if you have any questions, please leave them down below. Otherwise, I'll see everyone in the next practice video

An AM radio station broadcasts at 1000 kHz and its FM partner broadcasts at 100 MHz. Calculate and compare the energy of the photons emitted by these two radio stations.

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