Transition Metals:Oxidation States

by Jules Bruno
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Hopefully, guys attempted to do on your own. Now let's take a look at it together. Here we have cobalt, which is X again. And here we have ammonia, NH three and we have water again. Well, we know water is zero. Well, remember, ammonia is N H. Three N. H three is neutral, so it's oxidation. Number is zero. If I had given you ammonium ion ammonium, since it's plus one, it's oxidation. Number would have been plus one. Remember, this is ammonia. And this here is ammonium. Okay, so remember the difference. So this would also be zero. These halogen is here. Each would be minus one. Treated like a math problem. X one cobalt plus four Monje Z 20 0 plus one Water, which is zero plus one, bro. Mean, which is minus one plus two more, bro means each one is minus one equals the charge of zero. So here this dropped off. This drops out X minus two minus one minus two equals zero X minus three equals zero. So here X equals plus three. So that would be the oxidation state of cobalt. Now, for this practice one. I want you guys to try to remember what is going on in terms off. This question is asking us which one has a greater metallic behavior. Okay, And remember, I kind of talked about this when we talked about oxidation states remember the small of the observation state? What does that mean? In terms of the types of bonds we form and the greater the observation state of the transition metal. What kind of bonds do we form? This is key to answering this question. Attempt to do it on your own and then come back and see how I approach the same question. Good luck, guys.