Ethene (C2H4) can be halogenated by this reaction:
C2H4(g) + X2(g...

Question

Ethene (C2H4) can be halogenated by this reaction: C2H4(g) + X2(g) ⇌ C2H4X2(g) where X2 can be Cl2 (green), Br2 (brown), or I2 (purple). Examine the three figures representing equilibrium concentrations in this reaction at the same temperature for the three different hal- ogens. Rank the equilibrium constants for the three reactions from largest to smallest.

Accepted Answer

Hello. In this problem, we are told for the reaction A plus X goes to form B where X is equal to see in blue and orange. And Ian gray to refer to the three images below showing the reaction at equilibrium at the same temperature were asked to arrange the equilibrium constant. For the three reactions. From smallest to largest beginning with our first image, our equilibrium constant is equal to the concentration of our product be over that of our reactant A and C looking at the number of each of these, we have then four B's shown in green, we have six A is shown in red and we have four CS shown in blue. This then works out to 0.17 looking at the second image our equilibrium constant. Then we have the concentration of our product B over the concentration of our reactant A and D. And so we have then six bees that are shown in green, we have forays shown in red and we have four D S shown in orange. This works out to 0.38. And for our last image, our equilibrium constant then is equal to our product be over reacting concentrations A and E. And so looking at the image, we have seven, he's shown in green, we have three A is shown in red and we have three ES shown in gray. This then works out to 0.78. So we already have our equilibrium constants written from smallest to largest. So in terms of the image, then one is less than two, which is less than three. So this is the order of increasing value of our equilibrium constant. Thanks for watching. Hope this help.

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