The O¬H bond lengths in the water molecule 1H2O2 are
96 pm, and t...

Question

The O¬H bond lengths in the water molecule 1H2O2 are
96 pm, and the H¬O¬H angle is 104.5°. The dipole moment
of the water molecule is 1.85 D. (b) Calculate the magnitude of the bond dipole of the O¬H bonds. (Note: You will need to use vector addition
to do this.)

Accepted Answer

Hi everyone here we have a question asking us to calculate the magnitude of the bond I pull of the sulfur hydrogen bonds. Using the following data, the sulfur hydrogen bond links in the hydrogen sulfide molecule are 134 PICO meters and the hydrogen sulfide hydrogen angle is 92.1 degrees. The dipole moment of the ammonia molecule is 0.95 d. So we have our sulfur and it's bonded to our hydrogen And it has an angle of 0.5. And here We have 0.475 d. And 0.950. So the co sign of theta equals adjacent over the hypotenuse. So the co sign of 46.5° Equals 0.475. The over X. So x equals 0.475. The over the co sign of 46.5° And that equals 0.690. And that is our final answer. Thank you for watching. Bye.

The O¬H bond lengths in the water molecule 1H2O2 are 96 pm, and the H¬O¬H angle is 104.5°. The dipole moment of the water molecule is 1.85 D. (b) Calculate the magnitude of the bond dipole of the O¬H bonds. (Note: You will need to use vector addition to do this.)

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