Here we're told that gold can be plated out of a solution containing gold 3 ion based on the following half reaction. Half reaction here is that says that for every one mole of gold 3 ion we absorb 3 moles of electrons to give us one mole of gold solid. Now here it says what mass of gold is plated by a 41 minute flow of 6.8 amps in terms of current.

Now here they're giving us units of time. In the beginning it's up to us first to change these minutes of giving into seconds of giving. So we're going to start out by saying we have 41 minutes. We need to convert it into seconds of given for everyone minute. It's 60 seconds right? Now that we have seconds, we're going to introduce current. Now remember current or AMS SO1 amp is equal to 1 coulomb per one second. So when I give me 6.8 amps here, it's equal to 6.8 coulombs per one second.

We want seconds to cancel slots, so we're going to put the one seconds on the bottom, 6.8 Coulomb's on the top. Now that we have Coulombs, we're going to have to go from seconds of given to charging given, and that's what we just did here. Next, we're going to go from charge a given to moles of electrons of given by utilizing Faraday's constant 96,045 coulombs per one mole of electrons.

Now that we have moles of electrons given, we're going to make the jump to moles of unknown. So we have to look at the coefficients in the balance equation and it is for everyone mole of my solid. I have 3 moles of electrons, so it's 3 moles of electrons for every one mole of gold. So moles of electrons can't slap. Now I have moles of gold here. We want mass, so we're going to end at grand.

So last thing is we're going to say for everyone mole of gold. According to my periodic table, we're going to say the atomic mass of gold is 196.967g of gold. So here, when we work this out, we're going to get 11.383 grams of gold. If we want to do it in terms of sick figs, this has two sig figs. This has two sig figs. So you can round to just 11 grams of gold. So here this will be our final answer.