Choose from the conjugate acid–base pairs HSO4- >SO42-, HF>F-, and NH4+>NH3 to complete the following equation with the pair that gives an equilibrium constant Kc 7 1. _____ + NO2 - S _____ + HNO2

Video transcript

Hey everyone were asked which conjugate acid base pair will complete the following equation, resulting in a K equilibrium. That is less than one first. Let's go ahead and define what it means when our K equilibrium is less than one. So when our K equilibrium is less than one, this means that the acid on the react inside is going to be weaker than the acid on the product side. Now that we have this information, all we need to do is look at the K. S. Of each acid. Starting with our reaction, we have Hydrofluoric acid. Now when we look at the K. A. Of Hydrofluoric acid, we find that it is 6.6 times 10 to the negative four. Now let's go ahead and look at hydrogen sulfate. When we look at the K. A. Of hydrogen sulfate, We find that it is 1.0 times 10 to the -2. So answer choice A can't be our answer since our K. A. Is higher than our K. A. Of our Hydrofluoric acid. Next looking at Cloris acid. When we look up the K. A. This comes up to 1.1 times 10 to the -2. Again, this means that Cloris acid is a stronger acid than our Hydrofluoric acid. Next looking at our hydrogen oxalate, when we look up the K. A. this is 5.3 Times 10 to the -5. Now this proves that hydrogen oxalate is a weaker acid than our Hydrofluoric acid. So it looks like answer choice E. Is going to be our answer. But let's go ahead and look at sulfurous acid when we look up the K. A. For sulfurous acid, this comes up to 1.3 times 10 to the negative two. So again, this is stronger than our Hydrofluoric acid. So answer choice C. Is going to be our final answer. Now. I hope that made sense and let us know if you have any questions.