Draw the products of the following reactions. Use curved arrows t...

Question

Draw the products of the following reactions. Use curved arrows to show where the pair of electrons starts and where it ends up. a.

b.

Accepted Answer

Hey everyone. And welcome back in today's video, we are going to solve the following problem for each reaction given below, determine the products also indicate where the pair of electrons starts and where it ends up using curved arrows. Below this problem, we are given two reactions. The first one is zinc bromide reacts with water. And the second one states that iron three chloride reacts with the chloride and iron. Now we are going to begin solving this problem by remembering the Louis asset based theory. According to this theory, assets and bases are classified as follows assets. Our electron pair except Ear's and basis our electron pair donors. When we previously discussed that the two structures contained zinc bromide and iron three chloride, we may simply recall that transition metals have freed the orbital's sing and iron, they are transition metals and therefore they have unoccupied the orbital's, these orbital's can be used to accept electrons. And this makes perfect sense saying bro might and iron three chloride, those will be our Lewis assets. So starting with the first problem, we are going to write down Z N B R two and we are going to draw that free unoccupied the orbital above sink, we are going to add A plus science illustrate that sing bromide reacts with H two. And now we are going to use curved arrows to illustrate how the reaction takes place, as we said before, bases are electron donors. And in this case, oxygen within water has two lone pairs. We're going to use one of the two lone pairs to illustrate how our Lewis base. In this case, water forms a bond with the Lewis acid, which in this case is in bromide. So the lone pair essentially flows towards that free orbital of sink and we are forming oxygen sink bond. So we are adding equilibrium arrows, we may start drawing our product by adding H T O adding one of the remaining lone pairs and oxygen and illustrating that oxygen sing bond that we have formed, adding sync to our structure And BR two. So now the world last thing we want to do here is just determined the formal charges, oxygen has three bonds. And whenever option has three bonds, we're adding a formal positive charge and Zing forms an additional bond to it. So since it accepts a pair of electrons, it will become negatively charged, it has a total of three bonds. So we are done, We got our structure and we are ready to move on to part two. For part two, we have a similar scenario. So we are going to write down F P C L three, that's iron, three chloride plus cl negative. We are going to add three long for lone pairs. Song the glory than I am. We already know that because aren't we quite has iron in it? It has a free D orbital that we are going to draw above iron. And the lone pair on the chlorate and iron tells us that the chlorate and iron must be our base electron pair donor. So let's circle one of the lone pairs. And let's show the electron flow from that lone pair towards the unoccupied the orbital of iron. We are then going to draw equilibrium arrows draw chlorine with three remaining loan pairs because one of them has been used in the formation of that chlorine iron bond. Then we're adding FECL three. Now because Iran has accepted that lone pair of electrons that must be negatively charged. So we are adding a negative charge above iron. For chlorine, we don't have to worry about any kind of formal charge because now it has three lone pairs and a single bond. So chlorine has no formal charge, meaning those are our answers. We are now going to label our final answers in green. So we have box damn, we are going to simply conclude that the correct answer to the multiple choice question is D because it corresponds to the two equilibrium reactions that we have thrown. Thank you for watching. And I will see you in the next video.

Draw the products of the following reactions. Use curved arrows to show where the pair of electrons starts and where it ends up. a. b.

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Draw the products of the following reactions. Use curved arrows to show where the pair of electrons starts and where it ends up. a.
b.