Write the equation that shows how a buffer made by dissolving CH3...

Question

Write the equation that shows how a buffer made by dissolving CH3COOH and CH3COO−Na+ in water prevents the pH of a solution from changing appreciably when

a. a small amount of H+ is added to the solution.

b. a small amount of HO− is added to the solution.

Accepted Answer

Hey everyone and welcome back. A student prepares a buffer solution by dissolving propane OIC acid and potassium propane weight in pure water. Right? The chemical equations that illustrate how the components of the buffer are able to prevent a drastic change in the ph of the solution. When the student adds number one, a small amount of H pleasant to the solution. Number two, a small amount of O H minus into the solution. Let's start solving the first part. And let's remember that buffers consist of in a general form H A which is a week assad and A minus which is the conjugate base of the weak acid. Now, in the first part, we are adding H plus which is an acidic component. Let's remember that assets react with the basis. So within this buffer, we have to choose the basic component which will react with the strong asset. The basic component is our conjugate base A minus and the two structures H A and A minus. They differ by a proton. If we look at the structures within our buffer, those are CH three CH two C 00 H. And if we exclude potassium iron as a non spectator that B CH three CH two C negative. So we can clearly see that economic asset is H hour week asset and pro panel eight hour conjugate base A minus. We already know that a strong acid will react with the basic component. And our basic component is pro panel eight. So we're going to write down a reaction between pro panel eight CH three CH two C negative in its a grass form wet H plus. And you may notice that this is a basic proton acceptance, the negative charge and oxygen will essentially attack the proton and it will oxygen will accept that proton to form an acid. So let's draw an arrow to clearly illustrate that this is an acid based reaction and the product is professionally Cassidy CH three CH 2 C O H. So we are forming more of the asset that is already present in our buffer solution. For reaction number two, a small amount of hydroxide this added into the solution and hydroxide is basic O H minus as a base, meaning it will react with the acidic component H A. We already know that yesterday component is propane, a weak acid. So we are going to draw CH three CH two C O H A quiz and we will add O H minus yes. The negative charge on oxygen will essentially attack an acidic proton forming pro panel weight, which is already in the buffer solution. So one of our products will be CH three CH C 00 negative acquiesce plus water H C O liquid. That's because of H minus accepts the proton. And then we are breaking our C 00 H bond or specifically oxygen hydrogen bond. To be more accurate, we can illustrate that as well. The negative charge on oxygen attacks hygiene. And then we are breaking the oxygen hydrogen bond, that's how we get our products. So let's label our final answers. Now for the first reaction, let's label it in a green box. And similarly, let's add another green box for the second answer. Based on these answers, we may conclude that the correct choice to the multiple choice question is C thank you for watching and I will see you in the next video.

Write the equation that shows how a buffer made by dissolving CH3COOH and CH3COO−Na+ in water prevents the pH of a solution from changing appreciably when a. a small amount of H+ is added to the solution. b. a small amount of HO− is added to the solution.

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