Draw the condensed and skeletal structures for each of the follow...

Question

Draw the condensed and skeletal structures for each of the following:
b. cyclooctyne

Accepted Answer

Hey everyone. And welcome back in today's video, we are going to draw the skeletal and condense structures that correspond to the name given below cycle time. now, from this name, we can extract several facts. Number one or a cyclo means that we have a ring structure. Cyclic structure helped Means seven or basically seven carbon atoms suffix sign means that we have a triple bond in our structure because it corresponds to a functional group or a class of compounds to be more accurate, which is called al kinds. So they have triple bonds, combining all of these facts together. We can conclude that our structure is a seven member drink that has a triple bond in it. So for the structure, we are going to draw seven carbon atoms in a ring first. So we have 12, we four, five sex seven. So we have seven carbon atoms and then we are creating a bond between the first and the seventh. We want to add our triple bond between any two carbon atoms. So we create our triple bond, let's make sure that the distances are a bit closer. So we clearly see that this is a triple bond. Okay. And now we want to add the remaining hydrogen atoms, the triple bonded carbons will not have any high jeans because they already have four bonds. However, all of the remaining carbon atoms only have two bonds. So we need to add two hydrants to each of them Because every carbon atom must have four bonds total. And that is our condensed structure because it only shows you C C C C bonds. Now, generally, we would only show a triple bond if it was a straight chain and keep our carbon carbon single bonds implicit, we would not show them. But because this is a ring, we're only keeping carbon hydrogen bonds implicit since otherwise, it's not really possible to visualize a ring structure if we have met these single bonds as well, right? So that makes sense and this corresponds to our condensed structure. And now, if you want to draw a skeletal structure, we simply want to omit our carbons and Hae Jin's and simply hide them, right? So we're going to draw a seven member ring. Let's see that. So we have two carbon atoms, then we have our third one, fourth, one, fifth, one, 61, seventh one. And now if we bond these two carbon atoms at the very end, we get our seven member grain. Let's count them 1234567, right? So we have our seven member grain and we simply want to add a triple bond between any two carbons. So let's suppose we choose these two and that's the same structure in is skeletal form. So this is why skeletal forms are so useful. We can simply through our carbon carbon chain and we will automatically take care of the number of implicit Hye Jin's. We will not need to worry about them. We're only focusing on the number of carbons, the positions of the substations, we have none of them and the our double or triple bonds. So that's it. Now, the only common that we have here is that if you look at the triple bond is that it doesn't look like these two carbon atoms form linear bonds are based on 180 degree angle. It's basically because we have a ring strain and we cannot really draw it linearly, right. Otherwise, if it was a straight chain, we would draw this bond as a linear bond, right, 180 degree angle bond. However, here we, we see that we have an acute angle here and this is basically because of the ring strain, we cannot create a line here. We can see that if we have at least an eight member drink and this is a seven member drink. So no worries about it. The main goal in this problem was to draw the condensed, the skeletal structures. We have done that. And based on our answer, we may conclude that the correct answer to the multiple choice question is c thank you for watching.

Draw the condensed and skeletal structures for each of the following: b. cyclooctyne

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