Draw the skeletal structures for the compounds in Problem 42.
d. ...

Question

Draw the skeletal structures for the compounds in Problem 42.
d. vinyl bromide 
e. 1,2-dimethylcyclopentene 
f. diallylamine

Accepted Answer

Hey everyone. And welcome back in today's video. We are going to draw the appropriate colossal structures for each of the following. Number one, vinyl chloride, number 213 day metro cycle vaccine and number three, a little vinyl, I mean, Let's start with number one To draw structure. # one, we have to recall what a vinyl group is. A vinyl group essential corresponds to two carbon atoms which are bonded to some other parents that we are considering. In this case, it's as vinyl chloride. So we are going to have chlorine bonds to the vinyl group. But now the vinyl group itself has two carbon atoms that we see. And between carbons, number one and two, we have our double bond. So we call this group a vinyl group. Now, essentially, if we take our final group and bonded to a chlorine, we will get a vinyl chloride. So we're going to draw a double bond between two carbon atoms. So we have siege two Bonded to Ch because the top carbon has three bonds and then that C responded to chlorine. So we can state that this is vinyl chloride. Now moving on to the 2nd 1, if we look at the parent, it says Cyclo Hacks Een cycle means that we have a ring hex means that we have six carbon atoms within that ring. And because it says in that means our ring will have one double bond. So we have Cyclo Elkin. So what we're going to do here, we're going to draw six carbon atoms in a ring first. So we have 12, three, four, five and six. We're just going to bond these carbon atoms in the ring. And we can essentially calculate 123456, we have six carbon atoms in our ring and that corresponds to a hexagon in skeletal structures. And now we want to add our double bond, we can add our double bond at any position because wherever we add our double bond, that will define positions one and two. So let's suppose that we add our double bond at the very top. That would be our position one and position to the double bond always starts at carbon number one and bonds to carbon number two. So now if we look at the name says, once we die metal cycle vaccine, we got psycho vaccine And we want to add to metal substitue ints because it says die metal at positions one and 3. So this is our carbon number one, we are going to draw one metal group ch three. That's our position number two. If we go clockwise and the adjacent position is our position. Number three. Once again, not just how we get 1, 2, 3, if we go clockwise, right. So that essentially corresponds to dimethyl because we have two metal groups. Cyclo vaccine is our parent indicating that there is a double bond for this L king. And that will be it. We got our structure, we can label this is our final answer for number two and moving on to the 3rd 1, it says that we have a little vinyl. I mean, first of all, let's remember that amines are formed whenever you start with ammonia, NH three and you are replacing either 12 or three hydrogen atoms with actual al kill groups. And in this case, it says a little vinyl. So let's recall what these groups are. We already know that a vinyl group is Two carbon atoms bonded by a double bond as we analyzed before. And part number one and an added little group is very similar. You will start by drawing two carbon atoms bonded by a double bond, but he will just add an extra carbon atom. So that would be seized to ch just as before. But then you will have an extra siege two bonded to your actual parent. Now because we have a little vinyl. I mean it means that two hydrogen atoms from ammonia have been replaced with these two substitute prints. So first of all, we are going to replace this hydrogen with an elite group and say this hydrogen with the vinyl group, we get the following structure. We can draw nitrogen, one of the hydrogen atoms will still be bonded to that nitrogen. But then let's suppose that on the left side, we draw our alittle group. So we need to draw three carbon atoms 23, we are going to add our double bond. And on the right side of nitrogen, we are going to draw our final group. So that's two carbon atoms one two and then we are going to add our double bond. So indeed, this is el el vinyl, I mean because we have nitrogen which still has one hydrogen and two hydrogen atoms from ammonia have been replaced with an elite group, 123 carbon atoms with a double bond at the end. And a vinyl group 12 carbon atoms with a double bond at the end. So that's our final structure for the third one. And looking at the three structures, we may simply conclude that the correct answer to the multiple choice question is d thank you for watching.

Draw the skeletal structures for the compounds in Problem 42. d. vinyl bromide e. 1,2-dimethylcyclopentene f. diallylamine

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