Show how you would synthesize the following alcohol by reducing a...

Question

Show how you would synthesize the following alcohol by reducing appropriate carbonyl compound.

(a) heptan-1-ol

Accepted Answer

Hey everyone and welcome back to another video. In today's lesson, we are going to learn how can three metal Beauty and 10 be synthesized by reducing a carbon metal compound. As the problem suggests, we are going to synthesize three metal Beauty and one Oh and to do that, we're going to draw a reaction scheme in which on the product side we have our product. So to draw our product, we first will understand that this is beautiful. So we are going to draw a four member chain at position number one, we are going to add an alcohol group and then Position number three has a metal group. So that's 123. There's a metal group over here. As the problem suggests, we're going to reduce a carbonell compound. So if we are forming that product by reduction, we can get our starting material by oxidation. Right? And first of all, we understand that this is a primary alcohol because the carbon that is bonded to oxygen, it has only one carbon neighbor. So if it's a primary alcohol, we may recall that oxidizing primary alcohols produces alga hides meaning if we think in reverse, if we simply oxidize that primary alcohol, we will get an alga hide. That said, we can just draw our results and al to hide so we can add four carbon atoms, then instead of having an alcohol group, we will have an AL to hide over here. So that be oh, age and then there is that metal group. So we got our Aldo hide. We understand that this is the al the height that we want to start with because if we reduce that, we will produce an alcohol. Right? When whenever we reduce AL the heights we get primary alcohol. So that makes perfect sense. The world last thing we want to understand is what kind of a reducing agent can we use. And there are two reducing agents that can reduce Aldo hides. One of them is a strong reducing agent, potassium aluminum. I tried and the other one is sodium World High Tribe. One of the two regions here works for us. Whether we use a strong one or a mild one, we still achieve the same conversion to that primary alcohol. That said, this is our general reaction scheme. We start with an AL to hide use either a strong or a mild reducing agent to form a primary alcohol. And now the correct answer choice to the small poachers question is a However, if you have any questions, don't have States, leave your comment down below in the comments section and thank you for watching

Show how you would synthesize the following alcohol by reducing appropriate carbonyl compound. (a) heptan-1-ol

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