Draw the condensed and skeletal structures for each of the follow...

Question

Draw the condensed and skeletal structures for each of the following:
e. 4,4-dimethyl-1-pentyne

Accepted Answer

Hey, everyone and welcome back, draw the skeletal and condensed structures that correspond to the systematic name given below 33 dimethyl one pen sign. Now to solve this problem, so we are going to draw an expanded or partial expanded structure because we have a suffix sign that would correspond to an alkaline. So there must be a triple bond involved in our structure. So let's just draw a triple bond now because it's as one time sign, the triple bond starts at carbon number one. So we can label this as our carbon number one. Now, ensign means that our parent chain must have a total of five carbon atoms. So that's 123, four and five. So we have five carbon atoms. The triple bond starts at carbon number one, that's our parent pen sign. And we simply want to understand that at position three, we have die metal di means two as a prefix metal is a C three group. So at carbon number three, we are going to create these two methods, substitutions which are CH three. Now, the last thing we want to do is just add the missing hydrogen atoms going from rights left. Position five has one bond. So it needs three Hae Jin's because carbon must have four bonds. Position four needs to Hye Jin's right. Position three needs no Hae Jin's because we have four bonds saying goes to position number two, it has four bonds. Position number one needs one hygiene because we have three bonds. So that's our structure. We want to draw its condensed structure and its collateral form. So to draw the condensed structure, we're just going to show that triple bond only because it corresponds to the main functional group, which is an alkaline here. And for all the single bonds, we're not going to worry about them. So that's how it goes. We start with H C because that's what we see on the left because here we have our triple bond, we definitely want to indicate the presence of that triple bond, which shows us that this is an al kind clearly. Then we are going to add our carbon, number two. Then we are going to add our carbon # three. And because that carbon has its own to metal substitutions, we are going to add parentheses which indicate that there is something bondage that carbon and that's something is a metal group. So we're going to ST siege three and add a subscript of two to indicate that there are two metal groups bonded to it. Now, we are going to stay siege too because that's our fourth carbon atom And finally, our 5th 1 is CH three. So this is our condensed structure and we are ready to label this is our final answer or the skeletal one. It's actually much simpler to choice skeletal structure. And this is why we use them in organic chemistry. It's basically because as long as you have your parent, that's five carbon atoms, you are just going to draw it. So first of all, we are going to draw that triple bond and let's throw it in red. So that would be our triple bond. So we have our two carbon atoms and we need a total of five. So we have one here. Two here. That's 34 and five, right? So now each corner or each verdicts corresponds to one carbon atom specifically, we have one here. The second one here, they're both within the triple bond. Then we have our verdicts over here. That's our 3rd 1/4 1, fifth one. So that's our parent. And we only need to take care of the substitution is shown. So we only have two substitution at position three basically here where we add two carbons, right? We need to add two lines showing two bonds and each of these corresponds to one carbon atom at this point, right. So these must be one carbon atom for this group and one carbon atom for that one. So let's see why this structure is the correct one. Remember that every carbon atom must have four bonds. So this is your first one. It has three bonds. So four minus three gives you one implicit hydrogen. We have it. Your next carbon has four bonds. Four minus four is zero. Implicit Hae Jin's. You have it. The third carbon atom has four bonds. Four minus 40. Hye Jin's, you have it. The fourth one has two bonds. So you must have two implicit Hye Jin's. Yes, we have two hydrogen atoms. Now, for each of these C three, we have 123 of them. So if we only see one bond for each, there must be 4 -1, 3 hygiene items that are implicit and we indeed have them write three for each. So this means this should be our skeletal structure. Let's label this structures are finally answer. And based on our condensed structure and the skeletal one, we may conclude that the correct answer to the multiple choice question is, hey, thank you for watching.

Draw the condensed and skeletal structures for each of the following: e. 4,4-dimethyl-1-pentyne

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