Consider the following reaction:

HBr+-C≡N⇌Br−+HC≡N

g. What is t...

Question

Consider the following reaction:

HBr+-C≡N⇌Br−+HC≡N

g. What is the conjugate base of the acid on the right?

h. What is the conjugate acid of the base on the right?

Accepted Answer

All right. Hi, everyone. So for this question, let's provide the conjugate acid of the base and the conjugate base of the acid given on the right side of the following reaction. So let's begin by first recalling a few facts about the Bronson Lowry um acid base theory. So recall for a second that according to the Bronson Lowry theory, acids donate protons and assets donate protons, that bases can go ahead and accept. So basis except protons. Yeah, and there's kind of a back and forth there. So in order to figure out the conjugate acid of a base or the conjugate base of an acid, let's go ahead and treat it like an equation. So if we start with an acid, right, if we go ahead and we take our acid recall that we remove a proton, right? We subtract a proton to come up with its conjugate base. So that's our conjugate base. And similarly, right, if we go ahead and we take our base, we go ahead and we add a proton to your base to generate your conjugate acid. So with that being said, let's go ahead and let's look at the right side of the following reaction to figure out our asset and our base first. So chloride here on the right side is going to be your base. And the reason I know that is because it has a negative charge. And um if it has a negative charge, then it is capable of accepting a proton to become neutral. And if chloride is our base, then a seedling therefore must be our acid, which makes sense, right? Because acetylene has hydrogen on our carbon tear that can be deep rotated to generate a negative charge. So with that being said, let's go ahead and apply our formula, so to speak on our acid and our base. So in order to generate or figure out, I should say our conjugate acid, we take our base, right, which is chloride and we add a proton to it. So our conjugate acid is going to be chlorine with an extra hydrogen. And recall once again that when you add a proton um to something, you're also going to increase its charge by plus one. So we are going from a -1 charge on chloride to a neutral charge once we add that proton, and now let's move on to our conjugate base. So now what we do as we go ahead and we take our acid or acid early and we remove a proton from seedling. So that's gonna generate an an eye. Alright. We're gonna have a negatively charged carbon because that carbon is going to have an extra lone pair of electrons. Now, if adding a proton increases the charge by one, removing a proton is going to decrease the charge by one. So we're going from a neutral acid to a negatively charged conjugate base because of that. And so with that being said, this is going to be your answer for this question, right? And in particular, this corresponds to choice d in the multiple choice. So this is going to meet um like I said before, the answer to your question. And um if you stuck around to the end, thank you very much for watching. And I hope you found this helpful.

Consider the following reaction: HBr+-C≡N⇌Br−+HC≡N g. What is the conjugate base of the acid on the right? h. What is the conjugate acid of the base on the right?

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