(a) Compute the torque developed by an industrial motor whose out...

Question

(a) Compute the torque developed by an industrial motor whose output is 150 kW at an angular speed of 4000 rev/min.

Accepted Answer

Welcome back everybody. We are making observations about an electric motor inside of a grinder. We are told that it outputs 1.2 kilowatts or watts. And we are told that this happens at a rotational speed of 2000 revolutions per one minute. And we are tasked with finding how much torque is supplied by the electric motor. Well, we know that power is equal to torque times our rotational speed. If I just divide both sides by omega, we can cancel out the terms. And we get that our torque equal to our power divided by a rotational speed. But in order to plug rotational speed into this formula, we need to make sure we're in the right units here and our desired units is going to be radiance per second. Let's go ahead and convert real quick. We have that per one revolution is too I radiance and per one minute we have seconds. So these units will cancel and then we just multiply straight across and we get that our rotational speed is 209.4 radiance per second. Right now, we are ready to go ahead and plug in our variables into our formula here. So we get that our torque is equivalent to 1200 watts divided by our rotational speed of 209.4. Giving us a final answer of 5.73 Newton meters corresponding to our answer. Choice of D. Thank you all so much for watching. Hope this video helped. We will see you all in the next one

(a) Compute the torque developed by an industrial motor whose output is 150 kW at an angular speed of 4000 rev/min.

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