Beginning Algebra
Compute (3x+2)2(3x + 2)^2.
Factor x2+12x+36x^2 + 12x + 36 completely into a squared binomial.
Factor 36x2−2536x^2 - 25 completely over the integers.
Solve the equation (x+5)2−49=0(x + 5)^2 - 49 = 0 by factoring.
Expand (12x+3)2\(\left\)({\(\displaystyle\]\frac{1}{2}\)x+3}\(\right\))^2.
