Business Calculus
The cost function C(x)C(x)C(x) and the selling price of each article, p(x)p(x)p(x) are given below. Determine the profit function P(x)P(x)P(x).
C(x)=−0.03x2+70x+75C(x)=-0.03x^2+70x+75C(x)=−0.03x2+70x+75
p(x)=80−0.02xp(x) = 80 - 0.02xp(x)=80−0.02x
A tree is planted. The maximum possible height of the tree is 12.512.512.5 feet. The height of the tree is given by the following equation.
y=50040+2500e−0.75xy=\(\frac{500}{40+2500e^{-0.75x}\)}y=40+2500e−0.75x500, where xxx is in months and yyy is in feet.
Draw the graph of the function.
Find the value of f′(a)f^{\(\prime\)}\(\left\)(a\(\right\)) for the function f(x)=4x−1f\(\left\)(x\(\right\))=\(\sqrt{4x-1}\) when a=2a=2.
Use the following limit definition to determine the slope of the line tangent to the graph of ff at PP, where f(x)=43x−2f\(\left\)(x\(\right\))=\(\frac{4}{3x-2}\) and P(0,−2)P\(\left\)(0,-2\(\right\)):
mtan=limh→0f(a+h)−f(a)hm_\(\text{tan}\)=\(\displaystyle\) \(\lim\)_{h \(\to\) 0}{\(\frac{f(a+h)-f(a)}{h}\)}
The function kk and point VV are given. Determine all points PP on the graph of kk such that the line tangent to kk at PP passes through VV.
k(x)=x2+2x+1k\(\left\)(x\(\right\))=x^2+2x+1; V(4,9)V\(\left\)(4,9\(\right\))
Simplify the difference quotient f(x)−f(a)x−a\(\frac{f\left(x\right)-f\left(a\right)}{x-a}\) for the function f(x)=2x3−1xf\(\left\)(x\(\right\))=2x^3-\(\frac{1}{x}\).
Determine the tangent and normal lines to the function below at a specified point.
(x+y)2=4x+6\(\left\)(x+y\(\right\))^2=4x+6, (1,3)\(\left\)(1,3\(\right\))