Find the inverse f−$$1(x)f^{-1}$$\left(x\right)f−1(x) of each function (on the given interval, if specified).f(x)=2x2+1f\left(x\right)=\frac{2}{$$x^2+1$$}f(x)=x2+12, for x≥0x\geq{0}x≥0

Ch. 1 - Functions

Briggs - Calculus: Early Transcendentals 3rd Edition

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Briggs 3rd Edition

Ch. 1 - Functions

Problema 1.3.33

Capitolo 1, Problema 1.3.33

Find the inverse $f^{-1}$\left$(x$\right$)$ of each function (on the given interval, if specified).
$f$\left$(x$\right$)=$\frac{2}{x^2+1}$$ , for $x$\geq{0}$$

Guida verificata passo dopo passo

Start by setting the function equal to y: y = $\frac{2}{x^2 + 1}$.

Swap x and y to find the inverse: x = $\frac{2}{y^2 + 1}$.

Solve for y by first multiplying both sides by (y^2 + 1) to eliminate the fraction: x(y^2 + 1) = 2.

Expand and rearrange the equation to isolate y^2: xy^2 + x = 2, which simplifies to xy^2 = 2 - x.

Divide both sides by x to solve for y^2: y^2 = $\frac{2 - x}{x}$, and then take the square root of both sides to solve for y, considering the domain x $\geq$ 0 to ensure y is non-negative.

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Inverse Functions

An inverse function reverses the effect of the original function. If a function f takes an input x and produces an output y, the inverse function f^{-1} takes y back to x. For a function to have an inverse, it must be one-to-one, meaning each output is produced by exactly one input. This property ensures that the inverse function is well-defined.

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Finding Inverses Algebraically

To find the inverse of a function algebraically, you typically start by replacing f(x) with y. Then, you solve for x in terms of y, and finally, swap the variables to express the inverse as y = f^{-1}(x). This process often involves algebraic manipulation, such as isolating x and may require additional steps like checking the domain and range of the original function.

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Domain and Range

The domain of a function is the set of all possible input values (x-values), while the range is the set of all possible output values (y-values). When finding an inverse function, it is crucial to consider the domain and range of both the original function and its inverse. The range of the original function becomes the domain of the inverse, and vice versa, which can affect the validity of the inverse in certain intervals.

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