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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 10.4.39a

39–40. {Use of Tech} Lower and upper bounds of a series
For each convergent series and given value of n, use Theorem 10.13 to complete the following.


a. Use Sₙ to estimate the sum of the series.


39. ∑ (k = 1 to ∞) 1 / k⁷ ; n = 2

Guida verificata passo dopo passo
1
Identify the series given: \( \sum_{k=1}^{\infty} \frac{1}{k^7} \). This is a p-series with \( p = 7 \), which converges because \( p > 1 \).
Recall Theorem 10.13, which provides bounds for the remainder \( R_n = S - S_n \) of a convergent series with positive, decreasing terms. The theorem states that the remainder is bounded by the integral test inequalities:
\[ \int_{n+1}^{\infty} f(x) \, dx \leq R_n \leq \int_n^{\infty} f(x) \, dx, \]
where \( f(x) = \frac{1}{x^7} \) in this problem. To estimate the sum \( S \), first compute the partial sum \( S_n = \sum_{k=1}^n \frac{1}{k^7} \) for \( n = 2 \).
Next, calculate the integrals to find the bounds for the remainder:
\[ \int_3^{\infty} \frac{1}{x^7} \, dx \quad \text{and} \quad \int_2^{\infty} \frac{1}{x^7} \, dx. \]
Use these integral values to find the lower and upper bounds for the total sum \( S \) by adding them to \( S_2 \):
\[ S_2 + \int_3^{\infty} \frac{1}{x^7} \, dx \leq S \leq S_2 + \int_2^{\infty} \frac{1}{x^7} \, dx. \]

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Convergent Series

A convergent series is an infinite sum whose partial sums approach a finite limit. For example, the series ∑ 1/k^7 converges because the terms decrease rapidly and satisfy the p-series test with p = 7 > 1. Understanding convergence ensures that the sum S exists and can be approximated.
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Convergence of an Infinite Series

Partial Sums (Sₙ)

The partial sum Sₙ is the sum of the first n terms of a series and serves as an approximation to the total sum. For the series ∑ 1/k^7, S₂ = 1 + 1/2^7 provides an estimate of the infinite sum. Partial sums are fundamental in estimating series values and analyzing error bounds.
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Integration Using Partial Fractions

Theorem 10.13 (Bounds on Remainder of a Series)

Theorem 10.13 gives lower and upper bounds for the remainder (error) when approximating a convergent series by its partial sum Sₙ. It typically uses integrals to bound the tail of the series, allowing us to estimate how close Sₙ is to the actual sum. This theorem is essential for quantifying the accuracy of partial sums.
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Alternating Series Remainder
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41–44. {Use of Tech} Remainders and estimates Consider the following convergent series.


a. Find an upper bound for the remainder in terms of n.


43. ∑ (k = 1 to ∞) 1 / 3ᵏ

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72–75. {Use of Tech} Practical sequences

Consider the following situations that generate a sequence


a.Write out the first five terms of the sequence.


Drug elimination

Jack took a 200-mg dose of a pain killer at midnight. Every hour, 5% of the drug is washed out of his bloodstream. Let dₙ be the amount of drug in Jack’s blood n hours after the drug was taken, where d₀ = 200mg.

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71. Evaluating an infinite series two ways

Evaluate the series

∑ (k = 1 to ∞) (4 / 3ᵏ – 4 / 3ᵏ⁺¹) two ways.

a. Use a telescoping series argument.

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Find the first term a and the ratio r of each geometric series.


a. ∑ k = 0 to ∞(2/3) × (1/5)ᵏ

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{Use of Tech} Periodic dosing

Many people take aspirin on a regular basis as a preventive measure for heart disease. Suppose a person takes 80 mg of aspirin every 24 hours. Assume aspirin has a half-life of 24 hours; that is, every 24 hours, half of the drug in the blood is eliminated.


a.Find a recurrence relation for the sequence {dₙ} that gives the amount of drug in the blood after the nᵗʰ dose, where d₁ = 80.

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57–60. Heights of bouncing balls A ball is thrown upward to a height of hₒ meters. After each bounce, the ball rebounds to a fraction r of its previous height. Let hₙ be the height after the nth bounce. Consider the following values of hₒ and r.


a. Find the first four terms of the sequence of heights {hₙ}.


h₀ = 20,r = 0.5

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