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Ch. 4 - Exponential and Logarithmic Functions
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBlitzer 8th EditionCh. 4 - Exponential and Logarithmic FunctionsProblema 25
Capitolo 5, Problema 25

Evaluate each expression without using a calculator. log5 (1/5)

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Recall the definition of logarithm: \(\log_b a = c\) means \(b^c = a\).
Rewrite the expression \(\log_5 \left( \frac{1}{5} \right)\) as \(\log_5 5^{-1}\) because \(\frac{1}{5}\) is the same as \(5^{-1}\).
Use the logarithm power rule: \(\log_b (a^n) = n \log_b a\) to rewrite \(\log_5 5^{-1}\) as \(-1 \cdot \log_5 5\).
Since \(\log_5 5 = 1\) (because \(5^1 = 5\)), substitute this value back into the expression.
Multiply \(-1\) by \(1\) to find the value of the logarithm expression.

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Definition of Logarithms

A logarithm answers the question: to what exponent must the base be raised to produce a given number? For example, log_b(a) = c means b^c = a. Understanding this definition is essential to evaluate logarithmic expressions.
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Logarithms Introduction

Properties of Logarithms

Logarithms have key properties such as log_b(1) = 0 because any base raised to 0 equals 1, and log_b(b) = 1 since the base raised to 1 is itself. These properties help simplify expressions without a calculator.
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Change of Base Property

Negative Exponents and Their Logarithms

A fraction like 1/5 can be written as 5^(-1). Using this, log_5(1/5) becomes log_5(5^(-1)), which simplifies to -1 by the definition of logarithms. Recognizing negative exponents is key to evaluating such expressions.
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Zero and Negative Rules
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