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If you have 92 grams of nitrogen dioxide (NO_2), how many moles of NO_2 are present?
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2. Atoms & Elements
Mole Concept
Scelta multipla
How many moles of aluminum are present in 3.2 × 10^{25} atoms of aluminum?
A
0.53 moles
B
5.3 moles
C
1.9 moles
D
53.2 moles
Guida verificata passo dopo passo1
Identify the given quantity: 3.2 \(\times\) 10^{25} atoms of aluminum.
Recall that 1 mole of any substance contains Avogadro's number of atoms, which is approximately 6.022 \(\times\) 10^{23} atoms/mole.
Set up the conversion from atoms to moles using the relationship: \(\text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}}\).
Substitute the given values into the formula: \(\text{moles of Al} = \frac{3.2 \times 10^{25}}{6.022 \times 10^{23}}\).
Perform the division to find the number of moles of aluminum (do not calculate the final value here, just set up the expression).
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