What is the percent composition for carbon and hydrogen in eth...

Question

What is the percent composition for carbon and hydrogen in ethane C₂H₆?

Accepted Answer

Hello. Everyone in this video, we want to determine the mass percent of each element in 66 di bromo indigo, which is this compound right over here. So first things first, we're gonna go and calculate the molar mass of this giant molecule. So from carbons we have 16 atoms of carbon. Each atom has a mass of 12.107. And all these mass individual masses here can be found in your periodic table. Alright, so next adam that we're gonna deal with is hydrogen. We can see from molecule that's in the problem here that we have eight atoms of hydrogen each. Ha jin Let's put maybe a number will be better. Alright, so each hydrogen atom provides a mass of 1.00794. Then working our way down, we have coming next we have two items of grooming. Each will contribute a weight of 79.904. Next will be nitrogen. Again, there's two atoms. Each atom contributes 14.00674. In regards to mass. And lastly we have oxygen. Here. Again, there's two atoms. Each atom provides 15.9994. Alright, so we'll go ahead and Find the sum of this to get the molar mass of our 66 di Bruno Indigo. So once we put everything into the calculator we get the numerical value of 4, 20.55. Of course our unit for Mueller masses grams per mole. Now we can go ahead and use this mass to calculate the mass percent. So let's go ahead and recall that the mass percent equation is equal to the mass of our chemical. And this is going to be all over the total mass of the compound. Of course we need to multiply this by 100%. Alright, so let's go ahead and first start off with our carbon. So we're calculating here for the percent of carbon. Again, we have the mass of the chemical as our numerator. So we have 16 atoms of carbon age contributing a molar mass of 12. 107. And then we just calculate the total massive compound which is of course regarding that 66 di bergamo indigo. We said that was going to be 4, 20.55. And of course we have to multiply all this by 100%. So once we put that into the calculator we get the percentage of 45.76%. And that's going to be the percent of mass or the mass percent Of our compound. So we can go ahead and work down our list here, we'll go ahead and calculate next for the percentage of hydrogen. So the same exact thing we have eight atoms of hydrogen each contribute a molar mass of 1.00794. It's all going to be over the total mass of our compound. So for 20.055 and all this will be multiplied by 100%. This will go ahead and give us 1.92%. So 1.92% is the mass percent of the element in our compound. So next element that will deal with is going to be booming. So we have two atoms of burning each contribute a weight of 79.904. It's going to be over 4 20.55. Which again is the total mass of our compound. Simpleton point by 100% will give us a percentage for bombing to be 38.4%. So that's going to be the percentage of brimming. Next we'll deal with the percentage of nitrogen. Again, we have two atoms of nitrogen each contribute a weight of 14.00674. It's all going to be over 4 20.55. Multiplying by 100%. And that of course gives us once you put it into a calculator 6.67%. Alright, last element here, which is oxygen. So here we calculate for the percentage of auction. Again, we have two atoms of oxygen each contribute a molar mass of 15.9994 Is going to be over our total mass of the compound, which we calculate to be 40 or for 20.055. Let's find this by 100%. This will give us the product Of 7.6, 2%. So again, this is the percent or mass percent of Austrian in this compound. So here we have calculated the mass percent of each element in our 6/ eyebrow indigo compound.

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