Which of the following is not a correct formula unit? K 2 O MgO 2 Al 2 O 3 SrO

Welcome back everyone. We need to complete the following formulas by providing missing sub scripts for our given compounds. So right now we see for part one we have potassium bonded to an unknown subscript to our poly atomic ion which we recognize as sulfate, so recognize that this is a pol atomic ion because it's a charged ion with multiple atoms bonded to one another. We have sulfur bonded to three atoms of oxygen. And from memory we want to recall that cell fight Has a -3 an ion charge, meaning that when we recognize that potassium which is a metal is bonded here to our poly atomic ion. This combination yields a ionic compound meaning that we should recall. Ionic compounds involve a transfer of electric charge or of electrons. And so that minus three charge gets transferred to our potassium atom where potassium we recall is in group one A. Which is why our sulfide has a subscript of one which we which is implied we don't need to write it in. And so we would fill in that minus three charge as our missing subscript in the formula. So we would have K. three s. 0. three. And this would be our first answer for part one. Moving on to part two, we have S. R. With an unknown subscript bonded to our our foss fight poly atomic ion. So we have foss fight, Recall that foss fight has a -3 and ion charge and strontium Is considered based on its position on the periodic table. Being in group two a. It's considered a medal. And so this is the combination of yet again a medal plus a poly atomic ion phosphate meaning we have a transfer of electrons as we stated, forming our ionic compound. And so what we would have is the formation of strontium which will get as a subscript the charge from foss fight being three. And our foss fight which is going to get the charge of strontium. We recall again it's a group to a medal meaning it will form a plus two charge. And so foss fight is going to be P. +03 in parentheses with a subscript of two. And this would be our second answer for part two of the prompt. Now moving on to part three of our prompt. So there should be part three here we should recognize that we have yet again another polly atomic ion being in parentheses RSO three which we recognize as sulfite Recall that sulfide has a minus to an ion charge. Aluminum we want to recognize is also a medal. And on our periodic tables we find aluminum in group three a. Where we recall Adams in group three a form a plus three caddy in charge. And so yet again we have the combination of a medal and a poly atomic ion to form our ionic compound where our aluminum gets the charge of our sulfide an ion which is a minus to charge. So it has a subscript of two and our cell fight in parenthesis is going to get the charge of aluminum as a subscript of three. And this would be our third and final answer to complete this prompt as each of our missing sub scripts filled in for the corresponding formulas to the given compounds. I hope everything I explained was clear. If you have any questions, leave them down below and I will see everyone in the next practice video.

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1. Intro to General Chemistry4h 5m

Classification of Matter
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Physical & Chemical Changes
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Chemical Properties
7m

Physical Properties
6m

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15m

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12m

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8m

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4m

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32m

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10m

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17m

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21m

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19m

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13m

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9m

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15m

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8m

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38m

Titrations: Weak Base-Strong Acid
41m

Titrations: Strong Acid-Strong Base
11m

Titrations: Diprotic & Polyprotic Buffers
32m

Solubility Product Constant: Ksp
17m

Ksp: Common Ion Effect
18m

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12m

Selective Precipitation
9m

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18m

19. Chemical Thermodynamics1h 51m

Spontaneous vs Nonspontaneous Reactions
7m

Entropy
23m

Entropy Calculations
13m

Entropy Calculations: Phase Changes
6m

Third Law of Thermodynamics
7m

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14m

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22m

Gibbs Free Energy And Equilibrium
14m

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Standard Reduction Potentials
9m

Intro to Electrochemical Cells
6m

Galvanic Cell
25m

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10m

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13m

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20m

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16m

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8m

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16m

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20m

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16m

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Intro to Radioactivity
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9m

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7m

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7m

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9m

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7m

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10m

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3m

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4m

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14m

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7m

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12m

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16m

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19m

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14m

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Introduction to Organic Chemistry
8m

Structural Formula
8m

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10m

Skeletal Formula
6m

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3m

Intro to Hydrocarbons
16m

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11m

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12m

Functional Groups in Chemistry
11m

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4m

The Alkyl Groups
9m

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13m

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6m

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8m

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11m

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11m

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9m

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5m

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4m

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8m

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7m

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7m

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4m

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4m

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3m

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7m

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4m

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9m

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8m

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7m

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6m

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4m

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3m

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3m

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4m

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10m

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Main Group Elements: Bonding Types
4m

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7m

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11m

Main Group Elements: Periodic Trends
7m

The Electron Configuration Review
16m

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20m

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4m

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11m

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8m

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7m

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7m

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7m

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7m

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12m

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12m

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4m

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6m

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3m

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11m

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7m

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11m

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10m

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10m

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5m

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7m

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11m

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9m

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22m

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8m

Isomerism in Coordination Complexes
17m

Orientations of D Orbitals
4m

Intro to Crystal Field Theory
10m

Crystal Field Theory: Octahedral Complexes
5m

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4m

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4m

Crystal Field Theory Summary
8m

Magnetic Properties of Complex Ions
9m

Strong-Field vs Weak-Field Ligands
6m

Magnetic Properties of Complex Ions: Octahedral Complexes
11m

3. Chemical Reactions

Writing Ionic Compounds

General Chemistry

3. Chemical Reactions

Writing Ionic Compounds

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Which of the following is not a correct formula unit? K₂O MgO₂ Al₂O₃ SrO

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Which of the following is not a correct formula unit? K2O MgO2 Al2O3 SrO

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Which of the following is not a correct formula unit? K₂O MgO₂ Al₂O₃ SrO