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Ch.13 - Properties of Solutions
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Non è quello che usi tu?Cambia libro di testo
Capitolo 13, Problema 52a

Calculate the number of moles of solute present in each of the following solutions: (a) 255 mL of 1.50 M HNO3(aq),

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1
Convert the volume from milliliters to liters by dividing by 1000.
Use the formula for molarity: \( M = \frac{n}{V} \), where \( M \) is the molarity, \( n \) is the number of moles, and \( V \) is the volume in liters.
Rearrange the formula to solve for the number of moles: \( n = M \times V \).
Substitute the given values into the equation: \( n = 1.50 \, \text{M} \times 0.255 \, \text{L} \).
Calculate the number of moles by performing the multiplication.

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Molarity (M)

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L). Understanding molarity is essential for calculating the amount of solute in a given volume of solution, as it directly relates the volume of the solution to the number of moles present.
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Molarity Concept

Volume Conversion

In chemistry, it is often necessary to convert between different units of volume. In this case, milliliters (mL) must be converted to liters (L) since molarity is defined in terms of liters. The conversion factor is 1 L = 1000 mL, which is crucial for accurately calculating the number of moles of solute in a solution.
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Common Conversion Factors

Calculating Moles from Molarity

To find the number of moles of solute in a solution, the formula used is: moles = molarity × volume (in liters). This relationship allows for the direct calculation of moles when both the molarity and the volume of the solution are known, making it a fundamental concept in solution chemistry.
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Molar Mass Calculation Example