(a) The activation energy for the isomerization of methyl isonitrile (Figure 14.6) is 160 kJ>mol. Calculate the fraction of methyl isonitrile molecules that has an energy equal to or greater than the activation energy at 500 K. (b) Calculate this fraction for a temperature of 520 K. What is the ratio of the fraction at 520 K to that at 500 K?
Ch.14 - Chemical Kinetics
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Non è quello che usi tu?Cambia libro di testo
Capitolo 14, Problema 53
Calculate the fraction of atoms in a sample of argon gas at 400 K that has an energy of 10.0 kJ or greater.
Guida verificata passo dopo passo1
Identify the relevant concept: The problem involves calculating the fraction of atoms with a certain energy in a gas, which is related to the Maxwell-Boltzmann distribution.
Use the Maxwell-Boltzmann distribution formula: \( f(E) = \frac{2}{\sqrt{\pi}} \left( \frac{E}{kT} \right)^{1/2} e^{-E/kT} \), where \( E \) is the energy, \( k \) is the Boltzmann constant, and \( T \) is the temperature in Kelvin.
Convert the given energy from kJ to J: Since 1 kJ = 1000 J, convert 10.0 kJ to Joules.
Calculate the exponent in the Maxwell-Boltzmann distribution: \( -E/kT \), where \( k = 1.38 \times 10^{-23} \text{ J/K} \) and \( T = 400 \text{ K} \).
Integrate the Maxwell-Boltzmann distribution from 10.0 kJ to infinity to find the fraction of atoms with energy greater than or equal to 10.0 kJ.

Risposta video verificata per un problema simile:
Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2mConcetti chiave
Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.
Maxwell-Boltzmann Distribution
The Maxwell-Boltzmann distribution describes the distribution of speeds (or energies) of particles in a gas at a given temperature. It shows that at higher temperatures, a greater fraction of particles have higher energies. This concept is essential for understanding how many argon atoms will have energies above a certain threshold, such as 10.0 kJ, at 400 K.
Video consigliato:
Percorso guidato
Maxwell-Boltzmann Distribution
Kinetic Energy and Temperature Relationship
The kinetic energy of gas particles is directly related to the temperature of the gas, as described by the equation KE = (3/2)kT for monatomic gases, where k is the Boltzmann constant and T is the temperature in Kelvin. This relationship helps in calculating the average energy of argon atoms at 400 K and determining the fraction that meets or exceeds the specified energy level.
Video consigliato:
Percorso guidato
Kinetic Energy Formulas
Boltzmann Factor
The Boltzmann factor, given by e^(-E/kT), quantifies the probability of a particle having energy E at temperature T. It is crucial for calculating the fraction of argon atoms with energies equal to or greater than 10.0 kJ. By applying this factor, one can derive the proportion of atoms that possess sufficient energy to exceed the given threshold.
Video consigliato:
Percorso guidato
Maxwell-Boltzmann Distribution
Pratica correlata
Domanda del libro di testo
1360
views
Domanda del libro di testo
(a) What factors determine whether a collision between two molecules will lead to a chemical reaction?
607
views
Domanda del libro di testo
The gas-phase reaction Cl(g) + HBr(g) → HCl(g) + Br(g) has an overall energy change of -66 kJ. The activation energy for the reaction is 7 kJ. (b) What is the activation energy for the reverse reaction?
505
views
Domanda del libro di testo
The gas-phase reaction Cl(g) + HBr(g) → HCl(g) + Br(g) has an overall energy change of -66 kJ. The activation energy for the reaction is 7 kJ. (a) Sketch the energy profile for the reaction, and label Ea and ΔE.
406
views
Domanda del libro di testo
(b) Does the rate constant for a reaction generally increase or decrease with an increase in reaction temperature?
455
views
