Balance the following equations. (a) CO(NH₂)₂(aq) + HOCl(aq) --> NCl₃(aq) + CO₂(aq) + H₂O(l)

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Identify the number of each type of atom on both sides of the equation. For the reactants: C = 1, O = 1, N = 2, H = 2, Cl = 1. For the products: C = 1, O = 2, N = 3, H = 2, Cl = 3.

Start by balancing the atoms that appear in the least number of compounds. In this case, balance the nitrogen atoms first. Since there are 2 nitrogen atoms in the reactants and 3 in the products, adjust the coefficients to balance the nitrogen.

Next, balance the chlorine atoms. There is 1 chlorine atom in the reactants and 3 in the products, so adjust the coefficient of HOCl to balance the chlorine.

Balance the oxygen atoms. There is 1 oxygen atom in the reactants and 2 in the products, so adjust the coefficients to ensure the oxygen atoms are balanced.

Finally, check the balance of hydrogen atoms. Adjust the coefficients if necessary to ensure that the number of hydrogen atoms is the same on both sides of the equation.

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