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Ch.7 - Thermochemistry
Tro - Chemistry: A Molecular Approach 6th Edition
Tro6th EditionChemistry: A Molecular ApproachISBN: 9780137832217Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 80

Instant cold packs used to ice athletic injuries on the field contain ammonium nitrate and water separated by a thin plastic divider. When the divider is broken, the ammonium nitrate dissolves according to the endothermic reaction: NH4NO3(s) → NH4+(aq) + NO3– (aq) In order to measure the enthalpy change for this reaction, 1.25 g of NH4NO3 is dissolved in enough water to make 25.0 mL of solution. The initial temperature is 25.8 °C and the final temperature (after the solid dissolves) is 21.9 °C. Calculate the change in enthalpy for the reaction in kJ. (Use 1.0 g/mL as the density of the solution and 4.18 J/g•°C as the specific heat capacity.)

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1
Calculate the mass of the solution using the density and volume: \( \text{mass} = \text{density} \times \text{volume} \).
Determine the temperature change (\( \Delta T \)) by subtracting the final temperature from the initial temperature: \( \Delta T = T_{\text{final}} - T_{\text{initial}} \).
Calculate the heat absorbed by the solution using the formula: \( q = m \cdot c \cdot \Delta T \), where \( m \) is the mass of the solution, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change.
Convert the heat absorbed (\( q \)) from joules to kilojoules by dividing by 1000.
Calculate the enthalpy change per mole of \( \text{NH}_4\text{NO}_3 \) by dividing the heat absorbed (in kJ) by the number of moles of \( \text{NH}_4\text{NO}_3 \) dissolved.

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