Domanda del libro di testo
Which of following ethers cannot be made by a Williamson ether synthesis?
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Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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TOC.tableOfContents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding31
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds: Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
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Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblema 96c,d
Bruice 8th EditionCh. 9 - Substitution and Elimination Reactions of Alkyl HalidesProblema 96c,dCapitolo 9, Problema 96c,d
For each of the following alkyl halides, indicate the stereoisomer that would be obtained in greatest yield in an E2 reaction.
c. 3-bromo-2,3-dimethylpentane
d. 3-bromo-3,4-dimethylhexane
Guida verificata passo dopo passo1
Step 1: Recall the mechanism of an E2 reaction. E2 reactions are bimolecular eliminations where a base removes a β-hydrogen, and the leaving group departs simultaneously, forming a double bond. The reaction is stereospecific, favoring the anti-periplanar geometry of the β-hydrogen and the leaving group.
Step 2: Analyze the structure of 3-bromo-2,3-dimethylpentane. Identify the β-hydrogens available for elimination. Look for hydrogens on carbons adjacent to the carbon bonded to the bromine atom. Consider the anti-periplanar geometry to determine which β-hydrogen can be eliminated.
Step 3: Determine the stereoisomer formed in the elimination of 3-bromo-2,3-dimethylpentane. The anti-periplanar geometry dictates that the elimination will occur in a specific direction, forming the most stable alkene. Stability is influenced by factors such as substitution (more substituted alkenes are more stable) and steric hindrance.
Step 4: Analyze the structure of 3-bromo-3,4-dimethylhexane. Similar to the previous case, identify the β-hydrogens adjacent to the carbon bonded to the bromine atom. Again, focus on the anti-periplanar geometry to determine which β-hydrogen can be eliminated.
Step 5: Determine the stereoisomer formed in the elimination of 3-bromo-3,4-dimethylhexane. Consider the anti-periplanar geometry and the stability of the resulting alkene. The most substituted alkene will generally be favored, and steric hindrance should also be taken into account.
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E2 Reaction Mechanism
The E2 (bimolecular elimination) reaction is a concerted process where a base abstracts a proton while a leaving group departs, resulting in the formation of a double bond. This mechanism typically requires a strong base and occurs in a single step, leading to the formation of alkenes. The stereochemistry of the substrate plays a crucial role, as the reaction favors anti-periplanar geometry for optimal overlap of orbitals.
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09:36
Drawing the E2 Mechanism.
Stereochemistry and Stereoisomers
Stereochemistry refers to the spatial arrangement of atoms in molecules and how this affects their chemical behavior. Stereoisomers are compounds with the same molecular formula and connectivity but different spatial orientations. In E2 reactions, the stereochemistry of the alkyl halide influences which stereoisomer is formed preferentially, often favoring the more stable trans or E isomer due to steric factors.
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Percorso guidato
1:38Polymer Stereochemistry Concept 1
Zaitsev's Rule
Zaitsev's Rule states that in elimination reactions, the more substituted alkene (the one with more alkyl groups attached to the double bond) is typically the major product. This is because more substituted alkenes are generally more stable due to hyperconjugation and the inductive effect. Understanding this rule helps predict which stereoisomer will be formed in greater yield during E2 reactions involving alkyl halides.
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01:18Defining Zaitsev’s Rule
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For each of the following alkyl halides, indicate the stereoisomer that would be obtained in greatest yield in an E2 reaction.
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For each of the following alkyl halides, indicate the stereoisomer that would be obtained in greatest yield in an E2 reaction.
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For each of the following alkyl halides, indicate the stereoisomer that would be obtained in greatest yield in an E2 reaction.
d. 3-bromo-3,4-dimethylhexane
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