Predict the product of the following reactions.
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Step 1: Identify the type of reaction. The presence of H2O suggests a nucleophilic substitution reaction, likely an SN1 mechanism due to the secondary alkyl bromide and the polar protic solvent (water).

Step 2: Determine the leaving group. Bromine (Br) is a good leaving group, and it will depart, forming a carbocation intermediate.

Step 3: Analyze the carbocation stability. The carbocation formed is secondary, but it is adjacent to a cyclopropyl group, which can stabilize the carbocation through hyperconjugation and ring strain relief.

Step 4: Predict the nucleophile's attack. Water (H2O) will act as the nucleophile and attack the carbocation, forming an alcohol group at the site of the carbocation.

Step 5: Consider stereochemistry. Since the reaction proceeds via an SN1 mechanism, the product will be racemic, meaning both enantiomers of the alcohol will be formed due to the planar nature of the carbocation intermediate.

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