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Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Non è quello che usi tu?Cambia libro di testo
Capitolo 22, Problema 69i

Predict the products of the following reactions.
(i) Chemical reaction diagram showing reactants and conditions for a Michael addition reaction.

Guida verificata passo dopo passo
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Step 1: Identify the reaction type. This is a Claisen condensation reaction followed by hydrolysis and decarboxylation. The Claisen condensation involves the reaction of an ester with a ketone in the presence of a base to form a β-keto ester intermediate.
Step 2: Analyze the reactants. The first reactant is ethyl acetoacetate (CH₃COCH₂COOCH₂CH₃), which is an ester with an acidic α-hydrogen. The second reactant is cyclohexanone, a ketone with an α-hydrogen. The base used is sodium ethoxide (NaOCH₂CH₃), which will deprotonate the α-hydrogen of the ester to form an enolate ion.
Step 3: Mechanism of the Claisen condensation. The enolate ion formed from ethyl acetoacetate will attack the carbonyl carbon of cyclohexanone, leading to the formation of a new C-C bond. This results in a β-keto ester intermediate after the elimination of the ethoxide ion.
Step 4: Hydrolysis and decarboxylation. The β-keto ester intermediate undergoes hydrolysis in the presence of acid (H₃O⁺), converting the ester group into a carboxylic acid. Upon heating, the carboxylic acid undergoes decarboxylation, releasing CO₂ and forming the final product.
Step 5: Predict the product structure. The final product will be a substituted cyclohexanone with the new substituent derived from the ethyl acetoacetate reactant. The exact structure can be determined by tracing the connectivity formed during the Claisen condensation and subsequent steps.

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