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Ch. 6 - Confidence Intervals
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoLarson 8th EditionCh. 6 - Confidence IntervalsProblema 6.R.15
Capitolo 6, Problema 6.R.15

In Exercises 13–16, (a) find the margin of error for the values of c, s, and n, and (b) construct the confidence interval for using the t-distribution. Assume the population is normally distributed.
c = 0.98, s = 0.9, n = 12, xbar = 6.8

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Step 1: Identify the formula for the margin of error (E) when using the t-distribution. The formula is E = t * (s / sqrt(n)), where t is the critical value from the t-distribution table, s is the sample standard deviation, and n is the sample size.
Step 2: Determine the degrees of freedom (df) for the t-distribution. The formula for degrees of freedom is df = n - 1. In this case, n = 12, so df = 12 - 1 = 11.
Step 3: Look up the critical value (t) for a confidence level of c = 0.98 and df = 11 in the t-distribution table. This value corresponds to the two-tailed critical value for a 98% confidence level.
Step 4: Substitute the values of t, s, and n into the margin of error formula E = t * (s / sqrt(n)). Use the given values: s = 0.9 and n = 12. Simplify the expression to calculate E.
Step 5: Construct the confidence interval using the formula: Confidence Interval = x̄ ± E, where x̄ is the sample mean. Substitute x̄ = 6.8 and the calculated margin of error (E) to find the lower and upper bounds of the confidence interval.

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Margin of Error

The margin of error quantifies the uncertainty in a sample estimate. It is calculated using the critical value from the t-distribution, the sample standard deviation, and the square root of the sample size. A larger margin of error indicates less precision in the estimate, while a smaller margin suggests greater reliability.
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Finding the Minimum Sample Size Needed for a Confidence Interval

Confidence Interval

A confidence interval provides a range of values within which we expect the true population parameter to lie, with a specified level of confidence. It is constructed by adding and subtracting the margin of error from the sample mean. For a confidence level of 0.98, we use the t-distribution to find the appropriate critical value based on the sample size.
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Introduction to Confidence Intervals

t-Distribution

The t-distribution is a probability distribution used when estimating population parameters when the sample size is small and the population standard deviation is unknown. It is similar to the normal distribution but has heavier tails, which accounts for the increased variability in smaller samples. As the sample size increases, the t-distribution approaches the normal distribution.
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Critical Values: t-Distribution
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Domanda del libro di testo

[APPLET] The waking times (in minutes past 5:00 A.M.) of 40 people who start work at 8:00 A.M. are shown in the table at the left. Assume the population standard deviation is 45 minutes. Find (a) the point estimate of the population mean μ and (b) the margin of error for a 90% confidence interval.

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In Exercises 13–16, (a) find the margin of error for the values of c, s, and n, and (b) construct the confidence interval for using the t-distribution. Assume the population is normally distributed.

c = 0.99, s = 16.5, n = 20, xbar = 25.2

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In Exercises 27–30, find the critical values and for the level of confidence c and sample size n.

c = 0.90, n = 16

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In Exercises 19–22, let p be the population proportion for the situation. (a) Find point estimates of p and q, (b) construct 90% and 95% confidence intervals for p, and (c) interpret the results of part (b) and compare the widths of the confidence intervals.

In a survey of 73,901 college graduates, 23,991 obtained a postgraduate degree. (Adapted from Gallup)

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In Exercises 13–16, (a) find the margin of error for the values of c, s, and n, and (b) construct the confidence interval for using the t-distribution. Assume the population is normally distributed.

c = 0.90, s = 25.6, n = 16, xbar = 72.1

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In Exercise 19, would it be unusual for the population proportion to be 38%? Explain.

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