Domanda del libro di testo
The bearing of a lighthouse from a ship was found to be N 37° E. After the ship sailed 2.5 mi due south, the new bearing was N 25° E. Find the distance between the ship and the lighthouse at each location.
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Ch. 7 - Applications of Trigonometry and Vectors
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891
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TOC.tableOfContents
- Ch. R - Algebra Review381
- Ch. 1 - Trigonometric Functions188
- Ch. 2 - Acute Angles and Right Triangles168
- Ch. 3 - Radian Measure and The Unit Circle155
- Ch. 4 - Graphs of the Circular Functions100
- Ch. 5 - Trigonometric Identities238
- Ch. 6 - Inverse Circular Functions and Trigonometric Equations158
- Ch. 7 - Applications of Trigonometry and Vectors148
- Ch. 8 - Complex Numbers, Polar Equations, and Parametric Equations15
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 38
Find the force required to keep a 3000-lb car parked on a hill that makes an angle of 15° with the horizontal.
Guida verificata passo dopo passo1
Identify the forces acting on the car: the weight of the car acts vertically downward, and the force required to keep the car parked acts along the hill's surface, opposing the component of the weight pulling the car downhill.
Resolve the weight of the car into two components relative to the hill: one perpendicular to the hill's surface and one parallel to the hill's surface. The component parallel to the hill is responsible for the car's tendency to slide down.
Use the formula for the component of the weight parallel to the incline: \(F = W \times \sin(\theta)\), where \(W\) is the weight of the car (3000 lb) and \(\theta\) is the angle of the hill (15°).
Substitute the given values into the formula: \(F = 3000 \times \sin(15^\circ)\).
Calculate \(\sin(15^\circ)\) using a calculator or trigonometric table, then multiply by 3000 to find the force required to keep the car parked on the hill.
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Resolving Forces on an Inclined Plane
When an object rests on a slope, its weight can be split into components parallel and perpendicular to the incline. The parallel component causes the object to slide down, calculated as weight times sine of the angle, while the perpendicular component presses into the surface.
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Percorso guidato
3:22
Example 2
Trigonometric Functions in Force Analysis
Sine and cosine functions relate the angle of the incline to the force components. Specifically, sine of the angle gives the ratio of the opposite side (parallel force) to the hypotenuse (weight), essential for determining the force needed to counteract sliding.
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Percorso guidato
6:04Introduction to Trigonometric Functions
Equilibrium and Static Friction
To keep the car stationary, the applied force must balance the downhill component of weight, achieving equilibrium. Understanding static friction or the required force to prevent motion is key, as it counteracts the tendency to slide down the hill.
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Percorso guidato
4:02Solving Linear Equations with Fractions
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Given u = 〈-2, 5〉 and v = 〈4, 3〉, find each of the following.
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Domanda del libro di testo
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Standing on one bank of a river flowing north, Mark notices a tree on the opposite bank at a bearing of 115.45°. Lisa is on the same bank as Mark, but 428.3 m away. She notices that the bearing of the tree is 45.47°. The two banks are parallel. What is the distance across the river?
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