if-80-ml-of-0050-m-edta-is-added-to-50-ml-of-0100-m-metal-ions-what-is-the-conce

Question

If 80 mL of 0.050 M EDTA is added to 50 mL of 0.100 M metal ions, what is the concentration of free-floating metal ions before the equivalence point?

Accepted Answer

7.69 x $$10^{-3} M$$

Answer

2.50 x $$10^{-3} M$$

Answer

5.00 x $$10^{-3} M$$

Answer

1.00 x $$10^{-2} M$$