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Scelta multipla
Write the complex number in standard form.
A
3+4i
B
9+16i
C
3+34i
D
313i
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1
Identify the expression given: \(\frac{9 + \sqrt{-16}}{3}\). Notice that the square root of a negative number involves imaginary numbers.
Rewrite the square root of the negative number using the imaginary unit \(i\), where \(i = \sqrt{-1}\). So, \(\sqrt{-16} = \sqrt{16} \times \sqrt{-1} = 4i\).
Substitute \(\sqrt{-16}\) with \$4i$ in the original expression to get \(\frac{9 + 4i}{3}\).
Separate the fraction into two parts: \(\frac{9}{3} + \frac{4i}{3}\).
Simplify each fraction individually to write the complex number in standard form $a + bi$, where \(a\) and \(b\) are real numbers.