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Which of the following neutral atoms would be most likely to lose an electron and become a cation of +1?
A
A.
B
B.
C
C.
D
D.
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1
Step 1: Identify the number of electrons in the outermost shell (valence electrons) for each atom (A, B, C, and D) from the electron shell diagrams.
Step 2: Recall that atoms with fewer valence electrons tend to lose electrons more easily to achieve a stable electron configuration, often resembling the nearest noble gas.
Step 3: Analyze each atom's valence electrons: Atom A has 1 valence electron, B has 3, C has 5, and D has 7 valence electrons.
Step 4: Understand that atoms with 1 valence electron (like Atom A) are most likely to lose that electron to form a +1 cation because losing one electron results in a stable, full outer shell.
Step 5: Conclude that the atom most likely to lose an electron and become a +1 cation is the one with a single valence electron, which is Atom A.