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Find the antiderivative of the following function. f(x)=200
A
F(x)=0
B
F(x)=200+C
C
F(x)=200x
D
F(x)=200x+C
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1
Recognize that finding the antiderivative of a function involves reversing the process of differentiation. This means we are looking for a function F(x) such that F'(x) = f(x).
The given function is f(x) = 200. This is a constant function, and the antiderivative of a constant is the constant multiplied by x, plus an arbitrary constant of integration, C.
Using the antiderivative rule for constants, ∫a dx = ax + C, apply this to f(x) = 200. Here, a = 200.
The antiderivative of 200 is 200x. Don't forget to add the constant of integration, C, because the antiderivative is not unique without it.
Thus, the antiderivative of f(x) = 200 is F(x) = 200x + C.