Given the functions L(x)=x−2L\left(x\right)=x-2L(x)=x−2 and M(x)=x2M\left(x\right)=x^2M(x)=x2, calculate LM(5)\frac{L}{M}\left(5\right)ML(5)

LM(5)=325\frac{L}{M}\left(5\right)=\frac{3}{25}ML(5)=253

Given the functions L ( x ) = x − 2 L\left(x\right)=x-2 L ( x ) = x − 2 and M ( x ) = x 2 M\left(x\right)=x^2 M ( x ) = x 2 , calculate L M ( 5 ) \frac{L}{M}\left(5\right) M L ( 5 )

Okay. So let's see if we can solve this problem. So in this problem, we are given 2 functions. We're given l of x is equal to x minus 2, and m of x is equal to x squared. We're asked to calculate l over m of 5. Now what this notation is telling us right here is basically we need to take our function l divided by m and then evaluate whatever function we get at 5. So what I'm first going to do is find l over m of x. This is just dividing the 2 functions and getting a general the general function. So in this case, we're going to take our function l, which is x minus 2, and we're going to divide that by our function m, which is x squared. Now at this point, there's not much I can do to simplify this expression, so all I really need to do from here is evaluate this at an x value of 5. So we're going to have l of m of 5, we're going to take this x that we see and replace it with 5. So in this case, we'll have 5 minus 2 divided by 5 squared, and 5 minus 2 is the same thing as 3, and 5 squared is 5 times 5, which is 25. So this right here is the solution to the problem, and that is how you can divide and evaluate functions at certain x values.

Given the functions L(x)=x−2L\left(x\right)=x-2L(x)=x−2 and M(x)=x2M\left(x\right)=$$x^2M(x)=x2$$, calculate LM(5)\frac{L}{M}\left(5\right)ML(5)

LM(5)=325\frac{L}{M}\left(5\right)=\frac{3}{25}ML(5)=253

LM(5)=253\frac{L}{M}\left(5\right)=\frac{25}{3}ML(5)=325

LM(5)=53\frac{L}{M}\left(5\right)=\frac53ML(5)=35

LM(5)=35\frac{L}{M}\left(5\right)=\frac35ML(5)=53

0. Functions

Combining Functions

Calculus

0. Functions

Combining Functions

Difficoltà con Calculus?

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Given the functions $L$\left$(x$\right$)=x-2$ and $M$\left$(x$\right$)=x^2$ , calculate $$\frac{L}{M}$$\left$(5$\right$)$

$\frac{L}{M}\)$\left$(5$\right$)=\(\frac{25}{3}$

$$\frac{L}{M}$$\left$(5$\right$)=$\frac$53$

$\frac{L}{M}\)$\left$(5$\right$)=\(\frac{3}{25}$

$$\frac{L}{M}$$\left$(5$\right$)=$\frac$35$

Guida verificata passo dopo passo

First, understand the functions given: L(x) = x - 2 and M(x) = x^2. These are the functions you will use to calculate the expression L/M(5).

Substitute x = 5 into the function L(x) to find L(5). This means you will calculate L(5) = 5 - 2.

Substitute x = 5 into the function M(x) to find M(5). This means you will calculate M(5) = 5^2.

Now, use the values of L(5) and M(5) to find L/M(5). This involves dividing the result of L(5) by the result of M(5).

Simplify the fraction obtained from L(5)/M(5) to get the final expression in its simplest form.

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Given the functions $L\(\left\)(x\(\right\))=x-2$ and $M\(\left\)(x\(\right\))=x^2$ , calculate $\(\frac{L}{M}\)\(\left\)(5\(\right\))$