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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 10 - Sequences and Infinite SeriesProblema 10.6.63
Capitolo 10, Problema 10.6.63

45–63. Absolute and conditional convergence Determine whether the following series converge absolutely, converge conditionally, or diverge.
∑ (k = 1 to ∞) (−1)ᵏ⁺¹ · (k!) / (kᵏ)(Hint: Show that k! / kᵏ ≤ 2 / k², for k ≥ 3.)

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First, identify the general term of the series: \[a_k = (-1)^{k+1} \cdot \frac{k!}{k^k}\]. Since the series is alternating due to the factor \[(-1)^{k+1}\], we consider both absolute and conditional convergence.
To check for absolute convergence, examine the absolute value of the terms: \[|a_k| = \frac{k!}{k^k}\]. We want to determine if the series \[\sum_{k=1}^\infty \frac{k!}{k^k}\] converges.
Use the given hint to compare \[\frac{k!}{k^k}\] with \[\frac{2}{k^2}\] for \[k \geq 3\]. Since \[\frac{k!}{k^k} \leq \frac{2}{k^2}\], and the series \[\sum \frac{2}{k^2}\] converges (p-series with \[p=2 > 1\]), by the Comparison Test, the series of absolute values converges.
Since the series of absolute values converges, the original alternating series converges absolutely. Absolute convergence implies convergence regardless of the alternating sign.
Therefore, conclude that the series \[\sum_{k=1}^\infty (-1)^{k+1} \frac{k!}{k^k}\] converges absolutely.

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Absolute and Conditional Convergence

A series converges absolutely if the series of absolute values converges. If the original series converges but not absolutely, it is conditionally convergent. Understanding this distinction helps determine the nature of convergence for alternating or complex series.
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Choosing a Convergence Test

Comparison Test

The comparison test involves comparing a given series to a known benchmark series to determine convergence. If the terms of the given series are smaller than those of a convergent series, it also converges. This test is useful when bounding terms like k!/k^k by simpler expressions.
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Direct Comparison Test

Factorials and Exponential Growth

Factorials (k!) grow faster than polynomial terms but slower than some exponentials. The term k!/k^k involves factorial growth divided by exponential growth, and analyzing their relative rates is key to estimating term size and applying convergence tests effectively.
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Factorials
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13–52. Limits of sequences

Find the limit of the following sequences or determine that the sequence diverges.


{(n + 1)!⁄n!}

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11–86. Applying convergence tests Determine whether the following series converge. Justify your answers.


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13–52. Limits of sequences

Find the limit of the following sequences or determine that the sequence diverges.


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23–38. Divergence, Integral, and p-series Tests Use the Divergence Test, the Integral Test, or the p-series test to determine whether the following series converge.

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45–63. Absolute and conditional convergence Determine whether the following series converge absolutely, converge conditionally, or diverge.

∑ (k = 1 to ∞) (−1)ᵏ / k^(2/3)

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21–42. Geometric series Evaluate each geometric series or state that it diverges.  


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