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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 10.2.51

Limits of sequences
Find the limit of the following sequences or determine that the sequence diverges.


{nsin(6 / n)}

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1
Identify the sequence given: \(a_n = n \sin\left(\frac{6}{n}\right)\).
Recall the limit property for sine near zero: \(\lim_{x \to 0} \frac{\sin x}{x} = 1\).
Rewrite the sequence term to use this property by setting \(x = \frac{6}{n}\), so \(a_n = n \sin\left(\frac{6}{n}\right) = \frac{\sin\left(\frac{6}{n}\right)}{\frac{6}{n}} \times 6\).
Analyze the limit as \(n \to \infty\): since \(\frac{6}{n} \to 0\), use the limit property to find \(\lim_{n \to \infty} \frac{\sin\left(\frac{6}{n}\right)}{\frac{6}{n}} = 1\).
Combine the results to conclude that \(\lim_{n \to \infty} a_n = 6 \times 1 = 6\).

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Limit of a Sequence

The limit of a sequence is the value that the terms of the sequence approach as the index n goes to infinity. If the terms get arbitrarily close to a specific number, the sequence converges to that limit; otherwise, it diverges.
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Behavior of the Sine Function for Small Arguments

For values of x close to zero, sin(x) is approximately equal to x. This linear approximation, sin(x) ≈ x, is useful for evaluating limits involving sine functions where the argument tends to zero.
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Limit Laws and Substitution

Limit laws allow the evaluation of limits by breaking complex expressions into simpler parts. Substitution involves replacing variables with their limiting values when the function is continuous, facilitating the calculation of the sequence's limit.
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