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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 11 - Power SeriesProblema 11.RE.21
Capitolo 11, Problema 11.RE.21

Radius and interval of convergence Use the Ratio Test or the Root Test to determine the radius of convergence of the following power series. Test the endpoints to determine the interval of convergence, when appropriate.


∞
Σ (x/9)³ᵏ
k = 0

Guida verificata passo dopo passo
1
Identify the general term of the power series. Here, the series is given by \( \sum_{k=0}^{\infty} \left( \frac{x}{9} \right)^{3k} \). The general term \( a_k \) can be written as \( a_k = \left( \frac{x}{9} \right)^{3k} \).
Rewrite the general term to a simpler form if possible. Notice that \( \left( \frac{x}{9} \right)^{3k} = \left( \frac{x^3}{9^3} \right)^k = \left( \frac{x^3}{729} \right)^k \). This shows the series is a geometric series with ratio \( r = \frac{x^3}{729} \).
Apply the Ratio Test or Root Test to find the radius of convergence. For the Ratio Test, compute \( L = \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| \). Using the simplified form, \( L = \left| \frac{x^3}{729} \right| \). The series converges when \( L < 1 \), so \( \left| \frac{x^3}{729} \right| < 1 \).
Solve the inequality \( \left| \frac{x^3}{729} \right| < 1 \) to find the interval for \( x \). This simplifies to \( |x^3| < 729 \), which is equivalent to \( |x|^3 < 729 \). Taking cube roots on both sides gives \( |x| < 9 \). This means the radius of convergence \( R = 9 \).
Check the endpoints \( x = -9 \) and \( x = 9 \) by substituting them back into the original series to determine if the series converges at these points. Since the series is geometric with ratio \( r = \left( \frac{x}{9} \right)^3 \), at the endpoints \( r = \pm 1 \). Analyze convergence accordingly.

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Power Series and Convergence

A power series is an infinite sum of terms in the form a_k(x - c)^k, where c is the center. Understanding convergence means determining for which values of x the series sums to a finite value. The radius of convergence defines the distance from c within which the series converges absolutely.
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Intro to Power Series

Ratio Test and Root Test

The Ratio Test and Root Test are methods to determine the convergence of infinite series. The Ratio Test examines the limit of |a_{k+1}/a_k|, while the Root Test uses the k-th root of |a_k|. Both tests help find the radius of convergence by analyzing the behavior of terms as k approaches infinity.
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Percorso guidato
07:15
Root Test

Interval of Convergence and Endpoint Testing

The interval of convergence is the set of x-values for which the power series converges. After finding the radius, endpoints must be tested separately because convergence at these points is not guaranteed. Testing endpoints involves substituting them into the series and checking for convergence using appropriate tests.
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Percorso guidato
07:51
Choosing a Convergence Test
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Domanda del libro di testo

Radius and interval of convergence Use the Ratio Test or the Root Test to determine the radius of convergence of the following power series. Test the endpoints to determine the interval of convergence, when appropriate.


∞

Σ (x - 1)ᵏ/(k5ᵏ)

k = 1

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Domanda del libro di testo

Radius and interval of convergence Use the Ratio Test or the Root Test to determine the radius of convergence of the following power series. Test the endpoints to determine the interval of convergence, when appropriate.


∞

Σ x⁴ᵏ/k²

k = 1

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Domanda del libro di testo

Matching functions with polynomials Match functions a–f with Taylor polynomials A–F (all centered at 0). Give reasons for your choices.


a. √(1 + 2x)


A. p₂(x)= 1 + 2x + 2x²

B. p₂(x) = 1 − 6x + 24x²

C. p₂(x) = 1 + x − x²/2

D. p₂(x) = 1 − 2x + 4x²

E. p₂(x) = 1 − x + (3/2)x²

F. p₂(x) = 1 − 2x + 2x²

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Domanda del libro di testo

Find the remainder term Rₙ(x) for the Taylor series centered at 0 for the following functions. Find an upper bound for the magnitude of the remainder on the given interval for the given value of n. (The bound is not unique.)


ƒ(x) = ln (1 - x); bound R₃(x), for |x| < 1/2

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Domanda del libro di testo

Taylor series


a. Use the definition of a Taylor series to find the first four nonzero terms of the Taylor series for the given function centered at a.


f(x) = 2ˣ, a = 1

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Domanda del libro di testo

ƒ(x) = eˣ, a = 0; e-0.08


a. Find the Taylor polynomials of order n = 1 and n = 2 for the given functions centered at the given point a.

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